0-10V to 6-18V DC converter circuit

The question seems bonkers odd.
If you have 24v available, then just regulate that downwards, as it is much simpler to do.
If your 0-10v is a control signal then use that as an input to one of the vast array of voltage regulator chips which you can find with a simple search ('adjustable voltage regulator IC' typed into Google should do the trick).

You can hardly expect to actually generate or convert any voltage from zero....

This has the whiff of a project set by a lecturer whose mind has been engaged eldwhere...
Del

hello,

Thanks for your reply. I dont think adjustable voltage regulator will work as per my expectation. Whole circuit will be having supply voltage 24VDC. When

i/p is 0V o/p should be 6VDC,

i/p is 5V o/p should be 12VDC,

i/p is 10V o/p should be 18VDC. And this should be linear.

Thanks and regads,

Girish

Your last assumption in #3 might not be correct Del.

From: Tim Hawley Master Mech.

Hello Girish bkg,

I believe what you need is a DC voltage divider circuit.

See this link:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/voldiv.html

Open circuit behavior:

V1 will be your 24Vdc. R1 is connected in series and the resistive voltage drop of 6Vdc will be related to your required 18Vdc. R2 is in series but is also in parallel to the voltage out, so all you need to do is make R2 a variable resistive value. As the R2 resistive value increases your voltage output will increase.

I would setup a circuit like this, but keep in mind I have only put on paper and not tested it myself.

V1=24Vdc, R1= 1000 ohms, R2= 350 ohms, then Vout= 6.22Vdc

V1=24Vdc R1=1000 ohms R2= 3000 ohms then Vout= 18Vdc

Conclusion: An open circuit with a variable resistor ranging from 350 to 3000 ohms will give you your desired voltage range.

Most linear ten turn potentiometers range from zero(0) to 3000 ohms. So if you connect R2= 350 ohms across the center pin and one of the outer pins it will be in series. If you measure the resistance across the 2 outer pins it should start at 350 ohms and end at 3000 ohms.

As long as RL is held at zero (0) this circuit should to the trick.

Thevenin's Theorem Suggests that R3 can be added to the circuit to provide the desired output as well see example link:

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/thev2l.html#c1

Both of the links above allow you to put in your own voltage and resistance values and will do the calculations and provide the output results. Give it a try and let me know how you make out.

Best Regards, Tim

There is what is known as a voltage doubler, will turn your 10 volts dc into 20 volts dc. Talk to someone with experience in electronics. Hope this helps.

If I understand you correctly, your output is V_o=6+V_i* 1.2, so what you need is a linear Op Amp with an offset of 6.0V and a gain of 1.2. Any good Op Amp book should show you how.

Bingo!! And if it is homework, pick an op-amp that doesn't need a split rail supply!

Just out of interest, what do you need the 6-18 v for?

Thanks,

I m able to achive that.

Dear Friend,

(a) Use a V-F converter chip like LM331. Use 0-10 V Signal as input signal and stable operating power supply for this chip & others to follow.

(b) Connect Square wave frequency output thus available through an opto coupler to isolate this signal.

(c) Use another LM331 for F-V conversion.

(d) Calibrate as required.

(e) Split Isolated power supply will be needed, one for V-F and other for F-V.

Thanks and regards

Ashok Toshniwal, Bangalore, India

My comments are based on a design which we are actually using in equipment being supplied for installation on offshore oil platform where it works unattended 24x7.

Furthermore there is a difference between "Signal to be converted" & "Operating power supply, either AC or DC".

Thanks and regards

Ashok Toshniwal, Bangalore, India.

Actually you mean that you want to to use welknown Industrial-Control Protocol of

0-10V [other are -10V-0-+10V; 0-20mA; 5-20mA etc used in industry]

************ Quote **************

0-10 V is one of the earliest and simplest electronic lighting control signalling systems; simply put, the control signal is a DC voltage that varies between zero and ten volts. The controlled lighting should scale its output so that at 10 V, the controlled light should be at 100% of its potential output, and at 0 V it should at 0% output (i.e. "Off"). Dimming devices may be designed to respond in various patterns to the intermediate voltages, giving output curves that are linear for: voltage output, actual light output, power output, or perceived light output.

There are two possible, and incompatible, variations to the 0 to 10 V system:

0 to -10 V and 0 to +10 V.

....

0-10_V_lighting_control

****************** Quote Ends ****************

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Actually, using an OP Amp, the reference voltage would be 5.0v X 1.2 (gain) =6.0v.

... depending on whether the offset is added before or after the amplification.

www.powerint.com/ - you get plenty of help here!

thanks for all reply. I have ached it using op amp of gain 1.2 and offset of 6 volts.