Temperature of Insulation Plate

Apart from this sounding suspiciously like a homework question, it's not clear. Do you mean the temperature of the outside of the outer insulation layer? What's the difference between insulation plate and insulation layer? Is the whole set-up in air? What air temperature? Still air or forced draught?

If the 2 x 1000W is input continuously, the Al block will reach an equilibrium temperature at which heat loss = 2000W. This temperature could be estimated, but it may well not be 300°C. If the heat input is adjusted to maintain 300°C there's no need to specify the wattage. Then again, the heat input could be continued till 300°C reached, then switched off. In that case, the outside temperature will rise to a maximum, then decrease.

Whichever scenario it is, an important factor in heat transfer is the convection from the outer surface to the surronding fluid.

Cheers..........Codey

It is the temperature of the outside of the outer insulation layer. People can reach it by hand therefore temperature should be limited to max 45°C.

The first isolation plate can go to 600°c, but this a very weak plate, the second is has a high hot compressive strength but the max recommended service temperature is only 288°C.

The block is installed in a fume cupboard.

The heat input is adjusted to maintain 300°C with temperature regulator

I once made one also. Be careful that your temperature control is failsafe. Mine wasn't and the aluminum melted.

Since you claim to have the block of Al and are heating it, just measure it.

Or, is it homework?

it is under contruction

Never mind.

what Q value are you using? Q=lamda x A x (T2-T1)/d

Can you send a link with calculation examples.

Thanks

As I wrote look at the web offer via google at the domain "heat transfer".

There is a VERY good book from (I think) Lienhard you can download for free and get ALL theoretical support for all heat transfer situations as well quasi-static as dynamic (transient).

After you look at it I would suggest you recalculate the heating power and try to match it to the needed one if not you can get problems with the temperature regulation.

As a help you can put your equation also in the form Q/A=λ*Δθ/t all units in same system.

Water cool it? I mean the insulation plate. Then adjust at will, Ky.