Instrumentation

Assuming that 5 Bar corresponds to 4 mA and 15 Bar to 20 mA,

(x - 5)/(15 - 5) = (11.5 - 4)/(20 - 4). [Linear interpolation.]

x ≈ 9.69 Bar (9.6875 rounded to a more suitable precision; 9.7 might also do).

Please can you explain me the formula

Tornado's formula should be pretty self evident and as he stated makes the assumption that your sensor is a 4-20 mA linear output sensor. By coincidence all of the numbers in this example happen to be unique. So you can see a little clearer the origin of this formula by substituting the numbers with the units or units and numbers to see how the transformation happens. This will make sense though only if you have a good understanding of basic algebra.

Ahem, CR4 does not produce any products nor are we the service representative of any manufactured product. To find out how this particular pressure transmitter should function will require knowing the part number and contacting the manufacturer's support and/or web site information. They will tell you the differential or absolute pressure range the transducer was designed to work in and if the pressure output reading is a serial transmission, 0-10V, 4-20mA, 0-20mA or other proprietary communication technique. Once you have this information, if you still do not know the answer to your question then bring the results to us and we will translate.

Thank You

Is it calibrated?

Well assuming your sensor gives 4-20mA, so in your case 5bar will be 4mA and 15bar will be 20mA. Then if use linear interpolation i.e find x; then it will the following formula x-5/ 15-4 = 11.5-4/ 20-4 therefore that gives u x=9.69 bar.