What is the Braking Power Required

Energy (Kinetic) / dissipation in seconds = Power

However actual requirement will be (if mechanical drum type) depending upon the friction coefficient between the drum and the shoes friction coefficient etc...

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Hi

Thanks , anywhere my question is a bit vogue, lets take it way can you a formula for braking power of disc brake.

Thanks

Deepcut1

I would have thought you would need to know the weight to work out this problem.

tried to google it Any use ?

http://www.google.co.uk/search?q=braking+required+to+stop+a+150mm+diameter+shaft+rotating+3600+rpm&sourceid=ie7&rls=com.microsoft:en-gb:IE-SearchBox&ie=&oe=&rlz=1I7DKUK_en-GB&redir_esc=&ei=2PHzS-W9J4H40wS45pmkDQ

For starters you need to provide the desired ammount of time it will take to stop the mechanism. lets say for now you want it to stop in 1 second:

the energy of the disk is calculated as follows: T=0.5*Io*omega^2

where: Io=0.5*mass of disk*radius of disk^2

omega=speed of rotation in RADIANS per second (google on how to convert)

now, calculate the 'rorational energy' of the disk AND the rod itself(add them together), divide that by the time you want it to stop, and thats the power that you need.

in reaily, the power that you need will be much lower because friction will slow the system without any applied breaking power... but at least this should give you a rough idea of the maximum power you might need...

Strictly speaking, you don't "need" energy to stop it. In principle, you could recover energy.

Length and density of the rod, and disc details are needed to calculate total moment of inertia. With time available to stop it (not given by OP) can then calculate the torque the brake must apply.

Energy useful as a check on whether the brake is likely to overheat.

Cheers.............Codey

Braking power of anything depends on how fast you want to stop it.