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Participant

Join Date: Sep 2009
Posts: 3

Pump Required

05/22/2010 4:02 AM

I reqire a pump to pump sea water up 65mt pumping 15 m3 per hr over a distance of 900mt up a winding path

Pump to be submerged 10 m in the sea and will need to be able to withdraw pump while leaving pipe connected to quick coupling

We have 15 kw electrical power available

Help!

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#1

Re: pump reqired

05/22/2010 6:50 AM

Go to http://www.google.com/ to find some pump suppliers. Email their sales departments with your requirements.

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#2

Re: pump reqired

05/22/2010 7:25 AM

You can't pump water up a winding path. You'll have to carry it in buckets.

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#3

Re: pump reqired

05/22/2010 7:47 AM

May I do some simple mathematics?

15m3/Hr = 15000 Kg/Hr = 4.1667 Kg/Sec

900mt up means h=900

Potential Energy = mgh = 4.1667 x 900 x 9.81 = 36.787 KJ/sec

ie Power = 36.787 KW

(I am neglecting the

Extra density of salt water (1.03), Pressure drop (= head loss =energy lost) due to flow, the kinetic energy of the mass - even more enhanced since the path is winding ie with bends (- more head loss)

= 1/2mv2 = 2.08333 X V2 (Power) since mass is in per second

V is to be calculated from the crossection of the pipe,

Assuming an average velocity of 2m/sec, your pipe ID will be around 5cm However there you will have pressure drops approximately another 200m or so. So the better way will be to go for 75mm pipe or 100mm pipe ID say 4" pipe.

Then you have a controllable drop in about 2 digits.

And velocity V = about 0.5m/s

So the kinetic Power = 0.5 W and the power due to pressure drop may be about 1/2 KW so total is say 1KW towards this.

But the significant thing is going 900m up the mgh are not getting matched.

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#4

Re: pump reqired

05/22/2010 10:40 AM

We need to know the vertical difference between the sea at low tide and the elevation of the discharge point. The slope distance matters also for calculating pressure drop from pipe friction.

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#5
In reply to #4

Re: pump reqired

05/24/2010 2:57 PM

The vertical differance between low water and dicharge point is 65mt

The slope is gradual over the first 500mt to full head hight then dropes off to 45 mt then gradual back up to 65 mt will probarbly need to use 100mm pipe a pain to use

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#6
In reply to #5

Re: pump reqired

05/24/2010 10:56 PM

Thanks! Your OP said it correctly, but then some confusing answers occurred. The flow equates to about 66 gpm, for which a 3-inch (75-mm) pipe sounds about right. I don't have my pressure drop data here, so this is only a guess. For irregular terrain like this, I would favor HDPE pipe, which comes in coils and can be electrical-heat welded.

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#7
In reply to #6

Re: pump reqired

05/25/2010 10:40 AM

Thanks for that

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#8

Re: Pump Required

05/25/2010 4:14 PM

If I understood the Op properly, the height is 65 meters above sea level.15 M3 per hour is only about 4.5 gallons per minute.

65 meters positive head is around 92 psig.

900 meters is around 3000 feet.

Pressure drop at 5 gpm in 1.5 " pipe is .1psi per 100 feet.

3000 feet = about 3 psi drop. Add this to the positive head of 92 psig and you get 95 psig.

Select a pump that will deliver 5 gpm at your desired pressure plus the head.

Remember, sea water requires special pumps.

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