Center of Gravity

If you were able to make such nice 3D drawing, you should be able to, even manually, locate the cnter of gravity of each major subassembly and then find the hole assembly CG by this simplified problem. It's not really hard to do, if you think about it this way.

To be able to calculate the location of the center of gravity we need to length of all the members plus the mass of each member. The other thing is where exactly is the pivot point, I am assuming that it is the purple shaft, is that correct?

Another factor is that the frame structure appears to be designed to vary the height, if this is so then varying the height will have an effect on the center of gravity.

You can simplify the structure into simple components.

1. You can take the moments (weight of component x its arm length) around a chosen point.

2. Arm length = perpendicular distance from CG of that component to the chosen point.

3. Summation of these moments as a vectors must be equal Total moment of the assemply

(W1 x L1) + (W2 X L2) + .......... = W x L

W1, W2, ... are weights of components &

L1, L2, ... are perpenicular distances from CG of component to the point where the moment are taken about.

W is the total weight of the assemply & L is the distance from CG of the assemply to the specified point where we take the moment.

4. So, just calculating and defining L, we can locate CG of the assemply.

5. You can repeat the calculations for all positions you need for the structure.

the centre of gravity would change with the movement of this

item

do you want the centre of gravity at its point in drawing

center of gravity throught the operation of the system.

How to calculate the length an the thickness of the L angle element used in the above structure.

It doesn't look as though anything here weighs much compared to the "work piece" so just make sure that the stabilizers extend well beyond all points below all possible positions of the weight. It doesn't look very stable from side to side either, so you should consider horizontal stabilizers.

The movement of the scafolding up and down plus the movement of the object rotating cc up and to the left is going to create forces. If it's very slow, it shouldn't matter. Otherwise, it might tip itself over to the left and/or slide itself to the right as it moves. If you can't extend the legs out to the left, then I would use a counter weight on the lower frame (blue) or just anchor the whole thing to the floor. I would also use two wheels on each leg of those rolling cross bars (red), one above the lower frame and one below the lower frame to stabalize the upper frame. Or, just keep the one wheel and weld a second bar to the lower frame that it can fit between.

This looks all too much like another post regarding the angle iron and its size.

This thing looks overbalanced already and about to crash.

Is this a homework or technical school problems assignment.

In any event insufficient information to make an intelligent reply.