Electrical Question - Maximum Load?

Somebody moved the motor?

You've asked this question before! Look at your last post and then look in the tables for acceptable volt drop!

How did the thread title change?

Check back your text.The transformer(DT in this case) is specified in output power in KVA,prim Voltage(kV) and sec voltage(kV),what does it mean !oo KVA?.Please rectify your specs!

I'd move the transformer nearer to the motor it's cheaper!

Guessing 0.80 pf, 100kva → 80kw → 107hp. Thus 100hp is the maximum. Because of the long run, you need to check the cable size for voltage drop. 75hp might be more realistic.

It depends upon the method of starting and line parameters

You first must determine starting method, or adjust starting method based on motor size needed. A "rule of thumb" that has never failed me for sizing transformers based on starting method of a motor is:

• If starting Across-the-Line (DOL); Xfmr kVA = 3X motor HP (2.5X motor kW)
• If starting with RVSS starter (Solid State Soft Starter) = Xfmr kVA = 2X motor HP (1.5X motor kW)
• If starting with RVAT starter (Autotransformer) = Xfmr kVA = 1.5X motor HP (1.1X motor kW) as long as it will accelerate within the time limit of the AT
• Adjust all of the above for voltage drop, but keeping in mind that LV NEMA design motors typically are rated for a "Utilization Voltage" lower than line voltage already, i.e. 460V vs 480V (no idea if IEC motors do that).
  

So work those backward in your situation: in other words DOL HP = 1/3 of kVA then adjust for VD, RVSS HP = 1/2 of kVA etc. etc.

Hie

Thank you very much for the info.

Best regards

Ignatius