How to calculate axial load of wheels

Good lord this reeks of a homework problem. You just blew right past our FAQ listing didn't you.

Well I believe that the correct definition of an axial load is the load in the same direction as your axes. (Your professor or TA did define this term for you. If not ask them what they meant.) So as long as your cart continues to move in a perfectly straight line there will be no added axial load from straight motion. Of course there will be some axial load from the loading on the suspension system that will cause or try to roll the wheels of your cart. To calculate this you will have to know the spring constant of the suspension springs and all of the three dimensional geometry of the suspension bearing system. One should also know the torque setting used to secure the wheels to the axle and the pitch of the threads. This axial load will of course always be opposed by the normal force of the axle, that is until the threads get stripped. (You did ask for the axial load and not the net axial load.)

Now if you go into a turn, you will have to now know the radius of the turn and the angular velocity of the cart through the turn. (Are you writing this all down? Oh wait a minute I'm doing that already.) This will allow you to calculate the centripetal force required to maintain motion in a perfect circle for your 1000kg mass. But who makes a turn in a warehouse in a perfect circle. This will mean that you will have to do some two dimensional integral calculus to determine the angular acceleration as you move through your non-circular path. But don't forget that the axial load will not be perfectly evenly distributed to all four wheels. You will now have to go back to your suspension geometry to calculate the movement displacement change that will occur from making your turn. (Hint: if the center of gravity is not at axle height the inner and outer wheel load will be different.)

I hope that I helped you understand that bringing incomplete homework information will not help you here. Asking us to do your homework will not help you here. Telling us how much you do and don't understand your homework here can get you help here.

Good Day

redfred,

thank you so much of yr info.

ya... what he said! _^ga

You are hysterical - rflmao!!!

If the trajectory is not circular which means the curvature is variable it is enough to consider the radius of the osculator circle for the centripetal force of course the velocity has to be as well used for the computation. If velocity is variable then you must consider the velocity at the trajectory point where you compute the axial forces.

The maximal value is limited by wheels sliding, for a rough estimation this value can be used.

The other aspect is the non uniform weight repartition due to same force generated moment and angular position of load.

thanks nick name.

Centripetal acceleration: a = v²/r, in consistent units.

Another possible limitation is the overturning moment of the load, especially if it is tall in comparison to the vehicle width.

thanks a lots.