Resistors in Parallel

use "current division rule" or "voltage division rule"

Its simple

if you know the voltage say 10V,resistors be R1,R2(4 ohms,6 ohms)

Equivalent R=(R1XR2)/(R1+R2) (since parallel)

=24/10

=2.4 ohms

so total current=10/2.4

=4.16A

now via R1,Current=I(R2/(R1+R2))

=4.16(6/10)

=2.5A

Via R2=I(R1/(R1+R2))

4.16(4/10)

=1.664A

hope you understood.

please dont warn like that which shame for commentator,then question will be reduced,so appreciate them who are putting something to know the world.

can be simple or can be so difficult.

thanks i am of same thinking but some buddy want to criticize u is good thing.So i welcome criticize m. thanks all once again.

Apply Kirchoff's Law, Mate.

My Godfather's. What do they teach in schools these days? <Splutter, wheeze>