Hi All,
I am looking at some cable installations at one of our substations (66kV). The cable run will be about 500 metres, give or take, with XLPE 400mm^2 copper cable buried in terfoil arrangement. (Direct in ground with HDPE sheathing etc)
Some basic data is: Ampacity = 610 (assuming double bonded), Sheath resistance: 0.263ohm/km.
We are looking at only bonding the sheath at one end and my question is how do I know/calculate what the sheath voltage at the open end will be under normal and fault conditions and whether or not this will stress the insulation of the cable between the sheath and outer jacket?
From what I can gather the voltage rise will be a function of the current, say 10kA fault, and the screen impedance along the distance of the screen, but I gather it's not as simple as V=IZ as the fault current will not flow through the screen as it is open bonded at one end? Assuming there is an earthing conductor run with the cables I am at a bit of a loss as to how to calculate what the sheath voltage rise will be?
Thanks in advance.
Twinsen