Electrical

kW = 0.745699872×HP

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You have no manners when asking for help. I have read your previous posts, they're all asked in a rude manner.

Try asking a reasonable and intelligible question you may get help.

1 HP = 735 watts

so if ur motor is 3 phase rated for 415 voltage

then,

i=p/(v*1.17*pf)

consider pf=.8

i=18375/575

i=32 amps

Hi Zub KCL,

One may not be able to calculate the demand input current as the information you provided are not sufficient. However, the relationship between "HP" and"KW" is given as

IHP = 0.746KW

Therefore 25HP is (0.746*25) = 18.65KW or 18

Demand input current is calculated as follows:-

For Single phase pump.

I = P/(V * P.F)

Where I = Demand input current in Amps(A)

P= Power input in Watts(W)

V= Phase voltage in Volts(V)

P.F= Power factor

For 3 phase pump

I = P/(1.732 * V * P.F)

Where I = Demand input current in Amps(A)

P= Power input in Watts(W)

V= Line voltage in Volts(V)

P.F= Power factor

By substituting accordingly in the above formulae you can derive the input demand current.

The Web is a wonderful thing. You can speak to just about anyone in the world (if they are connected) and find out about most anything as well. I do feel for those who do not have a good grasp of the English language and try to make a post here, for information. If there is a question about what you might be trying to ask, seek someones help in translating to English. So your question and meaning can be more clear to others who might be inclined to help.

There are no bad questions, just some incorrectly ask.

You will need to provide a little more information, like:

• AC or DC?
• If AC, single or three phase?
• What voltage rating?
  
• What type of motor (there are various types of AC and DC motors (and among AC "standard" induction motors, there are variations related to how hard the load is to start))?
• Efficiency of the motor?
  
• Are you interested in the (steady state) load current or the startup current?

How accurately do you want the current? If you want an estimate you can use a formula for power, like I = P/E (or I = P/ (E * 3^-2) (the square root of 3) for 3 phase power). P is power in watts--multiply the Horsepower by 746 watts per Horsepower to get watts)

One HP = 746 watts. Also, you will experience locked rotor current draw when starting your motor; remember to compensate for that. Also, I agree with Tony.

I = (HP x 746)/(√3 x V x PF x Eff). (No one mentioned efficiency so far.)

0.85 is a reasonable estimate for PF (power factor); for a 25-HP motor, efficiency is probably between 0.90 and 0.95.