Capacity of Lobe Compressor Required to Convey Solid

For a small company in developing country, money and availability of technical expertise is always a constraint. The OP requirement is 2292kg/hr, so it is no where near those big silo system.

I think it is not a very difficult engineering problem , only require a bit of practical engineering approximation and experimentation, this is how you should go about doing it:

The force to move an object up an inclined path F=mg sin (angle of inclination),

The force due to air speed on a ball shape object F=1/2 * 1.22*V^2 *Cd*A; where Cd is coeff of drag (0.47 for ball shape); A is cross section area of bean.

From this equation, you get air speed v.

From bean flowrate Qb=2292 kg/hr=2292/700/3600=0.91 liter/sec, and given air speed v, you can find area occupied by bean flow, Ab; Ab=Qb/v.

Assume the bean flow will will occupy 30% of pipe area Ap, so you can find area of pipe, Ap= Ab/0.3.

So , the blower air flow rate Q=v*Ap

Watch out, above equation are in metric units.

Start with these approx values and adjust the RPM of the blower, flow rate is proportional to rpm. Motor power , from my earlier post 1 hp , perhaps to be on safe side, use 3 hp to give more room for adjustment.

The steps are , start with the blower with the required air flow rate, adjust rpm.