Pipe Loop Design

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flyinghigh Power-User Join Date: May 2008 Location: Arizona Posts: 355 Good Answers: 4	Pipe Loop Design 08/14/2011 12:13 PM
	the author posts the following equation: (1) ( (406*45)/(2h^2) ) =/< 208.3 which he converts to: (2) 87.79 = 4h^2 +120h which could be written as 4h^2 + 120h - 87.79 = 0 he solves for h: (3) h = 2.56 How does he get from (1) to (2)? How does he get from (2) to (3)?
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passingtongreen Guru Join Date: Aug 2009 Location: Glen Mills, PA. Posts: 2385 Good Answers: 114	#1 Re: pipe loop design 08/14/2011 12:41 PM
	(406*45)/208.3=87.71 4h^2=(2h)^2 was it written incorrectly? Don't know where 130h came from. __________________ In a time of universal deceit, telling the truth is a revolutionary act. George Orwell
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flyinghigh Power-User Join Date: May 2008 Location: Arizona Posts: 355 Good Answers: 4	#3 In reply to #1 Re: pipe loop design 08/15/2011 1:40 PM
	Yes, and I made the error. It should have been: ( (406 * 45)/(2h)^2 ) =/< 208.3 from which I get h = 4.68 The author got 2.56. He obviously converts the equation to a quadratic, but why?
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Tornado Guru Join Date: May 2009 Location: Richland, WA, USA Posts: 21017 Good Answers: 795	#4 In reply to #3 Re: pipe loop design 08/15/2011 4:50 PM
	For the (2h)² version, I agree with this answer. (I don't see where the 120h came from, either, and I don't think h = 2.56 is a solution to the resulting quadratic equation.) __________________ In vino veritas; in cervisia carmen; in aqua E. coli.
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Tornado Guru Join Date: May 2009 Location: Richland, WA, USA Posts: 21017 Good Answers: 795	#2 Re: pipe loop design 08/14/2011 12:45 PM
	He smoked a pipe and got loopy. (1) (40645)/2h² ≤ 208.3 (40645) ≤ (208.3)(2h²) (40645)/(208.3*2) ≤ h² h² ≥ 43.855... h ≥ 6.62 or h ≤ -6.62 __________________ In vino veritas; in cervisia carmen; in aqua E. coli.
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