Hi,
I would like to calculate the horsepower and fan speed necessary to operate a simple dust collection fan system at a quite high flow rate. Can anyone assist?
Here's the specs:
Fan: 8 bladed straight paddle fan, 11-3/4" wide paddles, 27" wheel OD. Some would call it a "materials handling" fan. I don't have a fan curve or even know the manufacturer of the fan, but since it is a plain old paddle fan someone must have some generic curves they would be willing to share!!
Pipe size: 17".
Discharge pipe: 75', 90 degrees of bends
Discharge into a 8' diameter cyclone
Inlet pipe to fan: 26', 180 degrees of bends.
Inlet distribution: Y's down to 3 x 10" pickup pipes, each 10' long, with 90 degrees of bends on each one.
Desired air velocity: 6,500 fpm.
The application is to move air from inside of a "saw box" at a high velocity to encourage air to flow into the many openings rather than "out". The basic problem we are trying to solve is that when sawing dry wood, the dust comes out of the saw box big time and causes lots of discomfort for people working in the area. Pulling a negative pressure in the box will reduce or eliminate this. The system will not be designed to pull the significant amount of sawdust these saws generate--99% of it falls out of the bottom of the sawbox and is guided into a waste conveyor in the basement. We are only trying to control the very light airborne dust that comes out of the machine elsewhere. Naturally, we have closed up as many of the openings as practiable!
The three pickup points are intended to be installed in the top of the sawbox, one over the infeed, one at the outfeed, and one over the enclosed outfeed belt when the lumber comes out of the sawbox.
Thanks in advance for your help!
Jon.
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