You cannot do this with just a transformer. DC does not conduct from the primary to the secondary of a transformer. Since what you ask for cannot be done with what you are looking for, the question now is what do you need?
If you are trying to take the power from one DC power source (AA battery) and convert this power to a different DC voltage power source then a DC to DC switching supply is what you need. To choose the correct supply you will need to know the voltage and maximum current will be needed at the output. You will also have to know the power available from your original DC power source. The drawback of this approach is that the output power will always be less than the power taken from the sole power source. You should also clarify if the output is isolated from the input. One also should know if the output is supposed to be regulated (constant voltage or current) as the input DC voltage changes.
If instead you are trying to track a small changing DC signal to a larger signal then what you are looking for is a DC amplifier. The gain desired must be specified for a circuit to be crafted. Usually a DC amplifier has at least two power sources available, the DC voltage to be measured and a voltage source slightly larger than the maximum output desired. The advantage of this approach is that very little power must be taken from the original DC signal. So the output power can easily exceed the power taken from the measured DC voltage.
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"Don't disturb my circles." translation of Archimedes last words
Same way, You can configure the same, by rectifiers in series, with capacitors in load side of each rectifiers, connected in series.
Of course, you have to design the power ratings of each components, as per your needs. PRV & current rating of each rectifier diodes should be taken care.
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Exploring the Science of Electricity
Basically, you convert DC to AC through a multi-vibrator circuit; step up the AC through a transformer and convert the AC back down to DC through a rectifier circuit. The power out will always be less than the power in.
If connected to a 12VDC supply, an ignition coil would produce no output (after some initial wobbles following the connection). The high voltage which produces the spark only occurs after the current is interrupted by the contacts opening.
Also (as redfred pointed out) when the primary current is interrupted, the secondary produces AC.
So - correct. It is not a DC step up.
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