First calculate its impedance. Second, divide that figure into the voltage. Job done.
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"Did you get my e-mail?" - "The biggest problem in communication is the illusion that it has taken place" - George Bernard Shaw, 1856
You have a point here. Perhaps the OP wants to get rid of harmonics and higher frequency pollution at that price. It surely will put the capacitor under test because these produce extra power. Take care. D
Surely there would be a circuit protective device somewhere?
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"Did you get my e-mail?" - "The biggest problem in communication is the illusion that it has taken place" - George Bernard Shaw, 1856