How is Hydraulic Pressure Accomplished?

Are you serious?

What does one pound of pressure applied to one square inch of area equal in PSI?

Please do another search in your text book, page 234.

Our friend Origo, if a student, is indeed a nonconventional student. He is a veteran, having served in the US Navy during WWII.

"I need to know how to multiply and calculate hydraulic PRESSURE in terms of pounds per square inch" I don't quite get what you are after... as in hydraulic head?

Fluid is essentially non-compressable.

Therefore, the pressure applied by the hydraulic system IS the pressure of the fluid.

You would then take the advice of Lyn (or part of it) to determine your mechanical advantage.

Is this what you are asking ?

most fluids resist being compressed try gasses if you want that

I said: Fluid is essentially non-compressable.

You said: most fluids resist being compressed

I think we're on the same page here Fredski.

Liquids are essentially non-compressible. Fluids include both liquids and gasses.

Cut me some slack RF...it's Florida and I'm hot...

From Wiki: Although the term "fluid" includes both the liquid and gas phases, in common usage, "fluid" is often used as a synonym for "liquid", with no implication that gas could also be present.

These should help...."Pascal's law states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container."

http://www.grc.nasa.gov/WWW/K-12/WindTunnel/Activities/Pascals_principle.html

http://www.hydraulicmania.com/

http://en.wikipedia.org/wiki/Hydraulics

http://hydraulik.empass.biz/

P = F/A

If you know the force divide by the area and the resulting number is the pressure. Note to self- if I can't find the information I am looking for on the Internet maybe I am asking for the wrong thing. Must remember this!

There are numerous ways of calculating pressure in one scale to pressure in another. Try this:

http://www.simetric.co.uk/

Hydraulic pressure multiplication

My mistake in the title. Evidently my text was not published by CR4. I should have worded the title as: "How is hydraulic pressure multiplied." In my text, I explained that most internet answers to my question reply about hydraulic force--not hydraulic pressure multiplication.

Origo, U.S.A.

The Multiplication of Force by a Hydraulic System - Wisc-Online.com

I think that an explanation is required: hydraulic pressure is the consequence of a outer resistance to the linear or rotatory motor.

One cannot program a pressure without a resistance which can be as well the container wall resistance to the pumped fluid.

One can only regulate or limit a pressure according to process or safety constrains.

If considering above statement the force generates the pressure and the system allows a pressure -if a limiter does not interfere- high enough to counter the force.

I still don't know what you really want that wasn't explained by TerraMan first, then others.

What is your ultimate objective?? Do you have some goal in mind??

But what happens if you reverse this?

i.e. put the force IN at F2 to use the force from piston F1 ?

jt

To the person who stole my copy of Microsoft office, I will get it back.

You have my word.

It is possible, of course, that the OP is genuinely seeking a means of pressure multiplication rather than force multiplication. A pressure of 1 kg-force/cm^2 within a hydraulic cylinder of 10 cm^2 cross-section acts on a piston. The force on that piston is 10kg. That piston has a circular extension of 1 cm^2 cross-section which serves as a piston in another hydraulic chamber. The pressure in that chamber is 10 kg/cm^2.

...Could somebody explain "Hydraulic Force"-what does it mean?

Allegorically of course...

Step on a water balloon. Hydro from Greek means water. Its the force applied by your foot that the water inside the water balloon receives between the floor and your foot that is spread out uniformly to the total surface area of the balloon. Your foot applied the force, but the hydraulic force it that force of the water against the sides of the balloon.

In the case of a water balloon, there is always (unless the water is frozen) a hydraulic force present. You can prove this by pricking the balloon with a pin. If it pops, the force is violently released. If you only punch a hole in it, a stream of water will flow out with that force until the force drops to zero. Then some water will remain inside, because the balloon has a normal volume before compression.