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Work Done Calculation to Rotate the Disk

08/20/2013 9:45 AM

A solid disk 0.15 mtr radius having mass 0.25 kg displaced at 10 degree with torque of 0.06 Nm,

then disk travels 350 degree in 2 seconds so what will the work done for 10 and 350 degree displacement?

Note : Initial angular velocity of disk is 0 for 350 degree displacement.

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#1

Re: Work Done Calculation to Rotate the Disk

08/20/2013 9:54 AM

How much are you willing pay for homework help? You're not expecting FREE help are you?

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#3
In reply to #1

Re: Work Done Calculation to Rotate the Disk

08/20/2013 11:24 AM

Rotational kinematic homework is better defined than this. The axis of rotation and center of mass is well defined in a homework assignment. This sounds more like somebody that should take this class instead of somebody in this class.

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#8
In reply to #3

Re: Work Done Calculation to Rotate the Disk

09/04/2013 4:37 PM

I suspect the question is not well worded to disguise it from a professor who would scan this site to see if his assignments were posted - - -

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#2

Re: Work Done Calculation to Rotate the Disk

08/20/2013 9:58 AM

About £30GBP per hour.

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#4

Re: Work Done Calculation to Rotate the Disk

08/20/2013 11:34 AM

Do your own homework. CR4 is not a homework cheat site. While some here might relish the opportunity to sharpen up old rusty skills by working the homework problem, consider the following and consider it well. If you cheat on your homework by using someone else's answers, you are only cheating yourself, because the purpose of any homework or other academic assignments is to help you learn - by practice, repetition, and self-discovery.

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#5
In reply to #4

Re: Work Done Calculation to Rotate the Disk

08/21/2013 1:15 AM

@Lyn: I fully endorse your post. Allow me to go a little further and recommend a book for Rupeshchoudharry to assist in the calculations: "Fundamentals of Engineering Science" by G.R.A Titcomb, revised by M. Jackson.

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#6

Re: Work Done Calculation to Rotate the Disk

08/21/2013 7:24 AM

Well said Lyn - kudos.

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#7

Re: Work Done Calculation to Rotate the Disk

08/21/2013 3:25 PM

i not only can't speak enlish i also don't understand it fully here's some stuff if it gets through "reply de-styler"::

Rectilinear & Rotational movment

For namings used under Quantity: look for exact refference from scientific documentation.

RectilinearRotational
QuantitySymbolFormulaUnitQuantitySymbolFormulaUnit
TimetsTimets
MassmkgMoment of InertiaI=Sum(Dm•r²)kg•m²
Distance

s

mRotation Angle

j

Sum(D

s)/R

rad, |Dim(rad)|=1
Velocity

v

s/¶t

m/sVelocity of Rotation

w

j/¶t=v/R

(rad)/s
Acceleration

a

v/¶t

m/s²Acceleration of Rotation

e

w/¶t=at/R

(rad)/s²
Impulse

p

=m•

v

kg•m/sMoment of Impulse

N

=I

w=Rxp

kg•m²(•rad)/s
Force Impulse

pf

p/¶t

N=kg•m/s²Moment of Force

M

=I

e=RxF

N•m(•rad)
Force

F

=

pf=m•a

N
EnergyE=mv²/2=masJ=N•mEnergyW=Iw²/2=Iejkg•m²(•rad²)/s²=
=N•m(•rad²)=J(•rad²)
WorkA=DE=F•¶s•CosjJ=N•mWorkA=DW=M•¶jN•m(•rad)
PowerP=¶A/¶tN•m/s=J/sPowerP=¶W/¶tN•m(•rad)/s=
=J(•rad)/s


some math related to s=et
x=xo+vot+aot²/2+...

Differences in switching between time and space bases
dx•(dt)

n

=e

t

dx•dt=e

t

x=e

t

dx/dt=e

t

dx/(dt)

n

=e

t

ln(x)•(dx)

n

=x

n/n!(ln(x)-SUM(1/m,m=1..n))

dt•dx=F(t,x)=x(t-1)=x•ln(x)-x
t=ln(x)
dt/dx=1/x
d

n(1/x)/(dx)n

=(-1)

n•n!/xn+1

!!! ( dx/dt = e

t ) / ( dt/dx = 1/x ) = ( et = x ) !!!
dt•dx=ln(et)dx=ln(et)dtet=//
[dx=dtet]: //=tetdt=tet-et=xt-x !!!


to be revised ...


EOF

+

FORMULAS Symbol Definitions:
  1. • -- multiply
  2. * -- multiply but may be other
  3. == -- same as
  4. ^ or ** -- power (but dominantly superscript) ap == a**p == a^p == exp(p•ln(a))
Pre-knowledge
  1. ( a ± b )2 = a2 ± 2ab + b2

  2. ( a ± b )3 = a3 ± 3a2b + 3ab2 ± b3

  3. ( a - b )( a + b ) = a2 - b2
    ( a - ib )( a + ib ) = a2 + b2

  4. ( a ± b )( a2 ± (-ab) + b2 ) = a3 ± b3

Series:
  • Sum[ c = (0,)1..n ] ( 2c ) = n( n + 1 ) = (0 +)2 + 4 + 6 + 8 + .. + 2n

  • Sum[ c = 1..n ] ( 2c-1 ) = n2 = 1 + 3 + 5 + 7 + 9 + .. + ( 2n - 1 )

  • Sum[ c = (0,)1..n ] ( c ) = n( n + 1 )/2 = (0 +)1 + 2 + 3 + 4 + 5 + .. + n

  • Sum[ c = 1..n ] ( c2 ) = n( n + 1 )•( 2n + 1 )/6 = 1 + 4 + 9 + 16 + 25 + .. + n2

  • Sum[ c = 1..n ] ( c3 ) = [n( n + 1)/2]2 = 1 + 8 + 27 + 64 + 125 + .. + n3

  • Sum[ c = 0..n ] ( ac ) = ( a( n + 1 ) - 1 )/( a - 1 ) = 1 + a + a2 + a3 + a4 + .. + an

Arith. progression:
  • An=A1+(n-1)d -- (0=A1),2,4,6,(8=A5), d=2

  • Sn=n(A1+An)/2=(2A1+(n-1)d)n/2 -- 0+2+4+6+8=5*(0+8)/2=(20+(5-1)2)5/2=20

  • Sn3=(An2+An1+(n3-n2-n1+1)(An2-An1):(n2-n1)n3/2 -- 0+2+4+6=(2+0+(4-2-1+1)(2-0)/(2-1))4/2=12

Geom. progression:
  • An=A1qn-1 -- (1=A1),2,4,8,(16=A5), q=2

  • Sn=A1(qn-1)/(q-1) -- 1+2+4+8+16=1*(25-1)/(2-1)=31

  • Sn->inf,q=abs(q)<1=A1/(q-1) -- 6/1+6/2+6/4+6/8+6/16+..+6/2n,n->inf=6/(1-1/2)=12

Trigonometry Sum of Angles
  1. Sin(a±b)=Sin(a)Cos(b)±Cos(a)Sin(b)

  2. Cos(a±b)=Cos(a)Cos(b)±(-Sin(a)Sin(b))

  3. Tan(a±b)=(Tan(a)±Cos(b)):(1±(-Tan(a)Sin(b)))

  4. Cot(a±b)=(Cot(a)Cot(b)±(-1)):(Cot(a)±Cot(b))

Sum of Functions
  1. Sin(a)±Sin(b)=2Sin((a±b):2)Cos((a±(-b)):2)

  2. Cos(a)+Cos(b)=2Cos((a+b):2)Cos((a-b):2)

    Cos(a)-Cos(b)=-2Sin((a+b):2)Sin((a-b):2)

  3. Tan(a)±Tan(b)=Sin(a±b):(Cos(a)Cos(b))

  4. Cot(a)±Cot(b)=Sin(a±b):(Sin(a)Sin(b))

Derived formulars
  1. Cos2(a)+Sin2(a)=1=(Cos(a)-iSin(a))(Cos(a)+iSin(a))=ei(-a)eia=(1/eia)eia

  2. Tann(a)=Cot-n(a)=(Sin(a)/Cos(a))n


  3. Sin(2a)=2Sin(a)Cos(a)

  4. Cos(2a)=Cos2(a)-Sin2(a)=2Cos2(a)-1=1-2Sin2(a)

  5. Tan(2a)=(2Tan(a)):(1-Tan2(a))

  6. Cot(2a)=(Cot2(a)-1):(2Cot(a))


  7. 1-Cos(a)=2Sin2(a/2)

  8. 1+Cos(a)=2Cos2(a/2)

  9. 1-Sin(a)=(Cos(a/2)-Sin(a/2))2

  10. 1+Sin(a)=(Cos(a/2)+Sin(a/2))2


  11. Sin(a/2)=±((1-Cos(a)):2)1/2

  12. Cos(a/2)=±((1+Cos(a)):2)1/2

  13. Tan(a/2)=±((1-Cos(a)):(1+Cos(a)))1/2=(1-Cos(a))/Sin(a)=Sin(a)/(1+Cos(a))


  14. 1+Tan2(a)=1/Cos2(a)

  15. 1+Cot2(a)=1/Sin2(a)


  16. Sec(a)=1/Cos(a)=(1+Tan2(a))1/2

  17. Cosec(a)=1/Sin(a)=(1+Cot2(a))1/2


Trig. Function Transfer Table

function argument

Sin(a)Cos(a)Tan(a)Cot(a)
Sin(a)(1-Cos

2(a))1/2

(Tan

-2(a)+1)-1/2

(Cot

+2(a)+1)-1/2

Cos(a)(1-Sin

2(a))1/2

(1+Tan

2(a))-1/2

(1+Cot

-2(a))-1/2

Tan(a)(Sin

-2(a)-1)-1/2

(Cos

-2(a)-1)1/2

Cot

-1(a)

Cot(a)(Sin

-2(a)-1)1/2

(Cos

-2(a)-1)-1/2

Tan

-1(a)



Trig. Function Table
Cos(a)0-101(3)

1/2/2

(2)

1/2/2

1/2
Sin(a)-10101/2(2)

1/2/2

(3)

1/2/2

a3Pi/2PiPi/20Pi/6Pi/4Pi/3
Tan(a)±inf0±inf01/(3)

1/2

1(3)

1/2

Cot(a)0±inf0±inf(3)

1/2

11/(3)

1/2



Arc Functions
  1. arccos(A)=±iln(A±(A2-1)1/2)

  2. arcsin(A)=(±)iln(±(1-A2)1/2-(±)iA), [±&(±)] are inipendent and [±&± or (±)&(±)] are syncronized

  3. i/2ln((1-iA):(1+iA))=arctan(A)=i/2ln((i+A):(i-A))

  4. i/2ln((iA+1):(iA-1))=arccot(A)=i/2ln((A-i):(A+i))


  5. arctan(A)+arccot(A)=Pi/2±2nPi, n is ±integer or 0

  6. ±(arctan(A)-arccot(A))=i/2ln(i(iA-±1):(iA±1))2=i/2ln(i(1-±iA):(1±iA))2

Hyperbolic Functions Sum of Angles
  1. ch(a±b)=ch(a)sh(b)±sh(a)sh(b)

  2. sh(a±b)=sh(a)ch(b)±ch(a)sh(b)

  3. th(a±b)=(th(a)±th(b)):(1±th(a)th(b))

  4. cth(a±b)=(1±cth(a)cth(b)):(cth(a)±cth(b))

Sum of Functions
  1. ch(a)+ch(b)=2ch((a+b):2)ch((a-b):2)

    ch(a)-ch(b)=2sh((a+b):2)sh((a-b):2)

  2. sh(a)±sh(b)=2sh((a±b):2)ch((a±(-b)):2)

  3. th(a)±th(b)=sh(a±b):(ch(a)ch(b))

  4. cth(a)±cth(b)=sh(a±b):(sh(a)sh(b))

Derived formulars
  1. ch2(a)-sh2(a)=1=(ch(a)-sh(a))(ch(a)+sh(a))=e(-a)ea=(1/ea)ea

  2. thn(a)=cth-n(a)=(sh(a)/ch(a))n


  3. ch(2a)=ch2(a)+sh2(a)=2ch2(a)-1=2sh2(a)+1

  4. sh(2a)=2sh(a)ch(a)

  5. th(2a)=(2th(a)):(1-th2(a))

  6. cth(2a)=(1+cth2(a)):(2cth(a))


  7. ch(a)-1=2ch2(a/2)

  8. ch(a)+1=2sh2(a/2)


  9. ch(a/2)=±((ch(a)+1):2)1/2

  10. sh(a/2)=±((ch(a)-1):2)1/2

  11. th(a/2)=±((ch(a)-1):(ch(a)+1))1/2=(ch(a)-1)/sh(a)=sh(a)/(ch(a)+1)


  12. 1-th2(a)=1/ch2(a)

  13. 1-cth2(a)=-1/sh2(a)

Area Functions
  1. arch(A)=ln(A±(A2-1)1/2)

  2. arsh(A)=ln(A±(A2+1)1/2)

  3. arth(A)=1/2ln((1+A):(1-A))

  4. arcth(A)=1/2ln((A+1):(A-1))


  5. arth(A)+arcth(A)=1/2ln(-(A+1):(A-1))2=1/2ln(-(1+A):(1-A))2

  6. ±(arctan(A)-arccot(A))=ln(i)=i(Pi/2±2nPi), n is ±integer or 0

Exponent Functions predef.-s
  1. a-x=1/ax

  2. Fm=0..3(x)=limn->+inf Sumc=0..n(x4c+m/(4c+m)!)

  3. ex=Summ=0..3(Fm(x))

  4. ln(A)=ln((1+x0)/(1-x0))=limn->+inf 2!Sumc=0..n(x02c+1/(2c+1))


    F0(-x) = F0(x)F0(ix) = 1F0(x)F0(-ix) = 1F0(x)
    F1(-x) = -F1(x)F1(ix) = iF1(x)F1(-ix) = -iF1(x)
    F2(-x) = F2(x)F2(ix) = -1F2(x)F2(-ix) = -1F2(x)
    F3(-x) = -F3(x)F3(ix) = -iF3(x)F3(-ix) = iF3(x)



    F0(x)=[ch(x)+Cos(x)]/2ch(x)=F0(x)+F2(x)=(ex+e-x)/2
    F1(x)=[ch(x)+Sin(x)]/2sh(x)=F1(x)+F3(x)=(ex-e-x)/2
    F2(x)=[ch(x)-Cos(x)]/2Cos(x)=F0(x)-F2(x)=(eix+e-ix)/2
    F3(x)=[sh(x)-Sin(x)]/2Sin(x)=F1(x)-F3(x)=(eix-e-ix)/(2i)


Properties of Logarithms
  1. logx(ab)=logx(a)+logx(b)

  2. logx(a/b)=logx(a)-logx(b)

  3. logx(ab)=blogx(a)

  4. logx(a)=logz(a)/logz(x)=1/loga(x)


  5. z1/ln(z)=e same as z=eln(z)


  6. Operations famyly::
    • ???,a$b=(area unknown requires 3D,4D numbers+ops. for simplex representation),a+b,ab,a*b,e.c.

    • a*b=eln(a)ln(b) -- arithmetical xor operation

    • a%b=eln(a)/ln(b) -- reverse xor-ing

    • unitive property: for every next generation applies a opn+1 b = eln(a)opnln(b)

    • Op. level base constants::
      • -inf $ a = a = "u say" -- something close to ??? 1/(1/-inf+1/a) ???
      • 0 + a = a
      • 1 a = a
      • e * a = a
      • ee (*"+1") a = a
      • e.c.
Trig.-Hyp. Relations
ch(x) =cos(i·x)ch(i·x) =cos(x)ch(-x) =ch(x)ch(-i·x) =cos(x)
sh(x) =-i·sin(i·x)sh(i·x) =i·sin(x)sh(-x) =-sh(x)sh(-i·x) =-i·sin(x)
cos(x) =ch(i·x)cos(i·x) =ch(x)cos(-x) =cos(x)cos(-i·x) =ch(x)
sin(x) =-i·sh(i·x)sin(i·x) =sh(x)sin(-x) =-sin(x)sin(-i·x) =-i·sh(x)
Complex-letter base formulas
  1. z = a + ib = Re(z) + iIm(z) = |z|eif = eln|z| + iarg(z)

    a = Re(z) -- real component of z,
    b = Im(z) -- imaginary component of z,
    |z| = abs[(a2+b2)1/2] -- module of z
    f = arg(z) = arctan(b/a) -- argument of z in rad, 180°=Pi rad.

    graphical::



  2. z = a - ib = Re(z) - iIm(z) = |z|e-if = eln|z| - iarg(z) ,in futher refferences z =def. @z
  3. |z| = (z@z)1/2 = |(Re2(z) + Im2(z))1/2| = e.c. , can be fetched stright if exists f(z)=@z, f(@z)=z

  4. arg(z) = arctan(Im(z)/Re(z)) = arctan(-i(z-@z)/(z+@z))

  1. (u@u)(w@w)=(uw)@(uw)

  2. |u||w|±1=|(uw)±1|

  3. u + @u = 2Re(u)

  4. u - @u = 2iIm(u)

  1. zc±1=e(ln|z|±ln|c|) + i(arg(z)±arg(c))

  2. zn=enln|z| + inarg(z)

    z1/n=e1/nln|z| + i/narg(z)

    1. zw = ewln(z) = e(Re(w)+iIm(w))(ln(z)+iarg(z)) =

    2. = zw = e(Re(w)ln|z|-Im(w)arg(z)) + i(Im(w)ln|z|+Re(w)arg(z))

  3. z=|z|eif=|z|(cos(f)+iSin(f))=a+ib -- exp., trig., arit. - forms of z

  4. eif=F0(if)+F1(if)+F2(if)+F3(if)=

    =(F0(f)-F2(f))+i(F1(f)-F3(f))=Cos(f)+iSin(f)

ex, ch(x), sh(x), Cos(x), Sin(x), F0(x), F1(x), F2(x), F3(x)

finest grid division's length = Pi/4

[eof]
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