We are using a six pole alternator coupled directly to induction motor of 2 pole to generate voltage at 150 Hz from 50Hz supply. Motor rating 5kW, Alternator (Generator) 5 KVA.
Syn. speed of motor = 120 f / P = 120 x 50 / 2 = 3000 rpm
Freq of voltage generated = 3000 x 6 /120 = 150 Hz.
The speed of rotation of motor / alternator(generator) is 2980 rpm.
Now we require supply with 100 Hz. If I de-couple the motor - alternator and drive the above alternator with pulley at approx 2000 rpm, will I get 100 Hz supply from this alternator.?? What will be new rated voltage and current of this alternator.??
Freq. of voltage required = 2000 x 6 / 120 = 100 Hz.
Thanks in advance
V.N.Prajapati