Greetings Everyone,
Are there anyone familiar with calculating the required tightening
torque for hydraulic tie rods (as shown in the pic). I am trying
to figure out how much torque I should use to tighten the nut. The tie
rod are made of mild steel (approximate yield of min 65ksi), the force
on the cylinder is around 20,000 lbf and I am using (6) 1/2" dia x 63"
Lg tie rods with 1/2-20 threads on each end. I used the machinery
handbook as reference using the following formula:
Fi=0.75*At*Sp (At=tensile stress area of bolt, and sp is the proof stress of the tie rod)
I then figured out the torque using T=0.2*Fi*d (Fi from above, 0.2
for mild steel with diameter within 1/4"-1" and d for tie rod diameter.
The only issue I have with the formula is that it does not take the
force of the cylinder in account or how long the tie rod is so I don't
think that is the correct procedure, can anyone offer some advice,
reading material, can PM me directly if you like or post here. Thank you
very much.