Lux Level Calculation for Street Light Intersection

The result, and the formula, will depend almost totally on where the road intersection is located.

City?

State?

Country?

Planet?

Solar system?

Universe?

You're new here.

You should:

1. Read the rules and FAQ's

its inside a city which the standard lux of intersection should be 30 to 35 lux

yes this is my first join here and your right i should have mention the location of the area intersection

thanks

What you really should do is contact the LOCAL authorities and ask them.

This is an international (worldwide) forum.

Requirements are different in different parts of the world/country/region/city.

Illuminating Engineering Society: IES
Outdoor Lighting Standards
Read, and follow the rules and FAQ's.

thanks

not this planet.....

Well, if they really are there <...i have...> then one could simply measure it.

sorry guys ( i have ) means project which its not exist yet , i use always to to get a useful informations from this site , i think all the details are provided in my question am just asking for help cause am in need for it and for support

Since we still don't know where you are, and since this is just for grins, go here :

Outdoor Lighting Suppliers - Alibaba.com and ask some of the suppliers to figure it out for you.

jerusalem is the city in Israel you know it ???

Oooooh. Is this a Geography test?

let me check my files

Download Final Report Lot 9: Public street lighting - EUP4LIGHT.net

Hiliom,

You really need to specify the type of luminaire and its manufacturer to get accurate results. The information you have provided is necessary, but not sufficient; it's like specifying everything about a space heater and asking how hot the room will get without specifying the size of the room.

The bulb, reflector, and lens configuration will determine the shape of the effective coverage. The manufacturer should provide that information to you, the ILE (Institute of Lighting Engineers) will provide the means to evaluate the info for your particular scenario. Welcome to CR4.

Alan

I think you'll need more than 250w, more like 1000w....

I use this program for lighting designs. Eliminates manual calculations. You can use the program for free for 30 days. After the 30 days is up, you may still do designs but you cannot print the photometrics.

http://www.visual-3d.com/software/download.aspx

You will obviously need to learn the program (relatively easy if you have any experience with 3D modeling). Furthermore, you will need an ies file for the light fixture in question. These can usually be acquired from the fixture manufacturers website. Good luck!

The wattage of the lamp is closely linked to the light output, but it is not a fix falue; it varies from one technology to the other, configuration of the lamp and reflector as well as the quality of the materials.

You need to know exactly what is the light intensity of the lamp in the unit that you prefer; and diminish that ammount by the inverse of the square of the distance.

For example, if you have an intensity of 2800 lux from a lamp located 1 meter away, you will measure 700 lux if you move it one meter further:

You have 2800 lux @ 1m, ok?

1m + 1m = 2m, the square of 2 is 4, the inverse of 4 is .25

2800 * .25 = 700 lux

Yes it looks awkward but is true, the light dims at a greater rate than the distance that you put in between. That is why you can see a spot of light below a lamp being sorrounded by darkness.