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Anonymous Poster #1

Standard Deviation Calculation

04/18/2014 5:45 AM

Hi,

For the streams of data 100,000; 90,000; 80,000; 70,000; 60,000; 50,000; 40,000;

(Probability %: 5, 10, 20, 30, 20, 10, 5)

I have calculated as: 20,000.(standard deviation: population)

But how does it come out as

Standard deviation of possible outcomes: 14,491 ??

(Capital Budgeting: Theory and Practice by Pamela P. Peterson)

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#1

Re: Standard Deviation Calculation

04/18/2014 8:50 AM

Did you weight the values according to their probabilities?

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Anonymous Poster #1
#2
In reply to #1

Re: Standard Deviation Calculation

04/18/2014 9:47 AM

but that way, we get expected values right? Do we also have to weigh the values according to their probabilities to calculate standard deviation? I calculated, mean, variance and square root of variance to calculate variance. How do use values for probability?

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#3
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Re: Standard Deviation Calculation

04/18/2014 8:20 PM

One way is to assume 5 entries each of 100,000 and 40,000; 10 each of 90,000 and 50,000; 20 each of 80,000 and 60,000, and 30 of 70,000; for a total N of 100.

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#5
In reply to #3

Re: Standard Deviation Calculation

04/18/2014 11:40 PM

Alternatively....

1 entry each of 100,000 and 40,000; 2 each of 90,000 and 50,000; 4 each of 80,000 and 60,000, and 6 of 70,000; for a total N of 20.

ie 100,90,90,80,80,80,80,70,70,70,70,70,70,60,60,60,60,50,50,40 (less typing and counting...)

Stick that lot in a calculator and you do get 14.491 (you can do the x103 in your head)

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#4

Re: Standard Deviation Calculation

04/18/2014 10:40 PM

Who cares about a poster who cannot go to the trouble of coming up with a nickname? A "nick" is just as anonymous, but it allows us to search your history, and frame an answer based on "getting to know you". Please consider it.

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#6

Re: Standard Deviation Calculation

04/19/2014 4:22 PM

I'm not going to do your homework for you but I'd be curious to know how you calculated your answer. Your data set is chunky and evenly divided, given the way the normal curve calculations are performed it would be unusual indeed to arrive at a round number answer for such a data set. My brain tells me it should be around 14,140. What did you do, a 2 sigma calculation by ignoring the outliers and dividing the 40,000 spread by two?

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