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Nitrogen Volume Calculation

09/03/2014 9:53 AM

Hi

I would like to know the nitrogen volume calculation

To pressurize 10 cubic meter of pipe line ,how much volume nitrogen required on the below condition ?

1. only to purge at positive pressure?

2. pressurize with 30psi ?

how much gallon of liquid nitrogen required fill 1 cubic meter at atm pressure?

how much gallon of liquid nitrogen required fill 1 cubic meter at 30psi pressure?

please share your stuff ..

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#1

Re: Nitrogen volume calculation

09/03/2014 10:16 AM

Please share your stuff first:

Gallons (undefined which gallon), psi, and cubic meters don't really go together. When you convert your units, what do you get?

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#7
In reply to #1

Re: Nitrogen volume calculation

09/04/2014 9:39 AM

Hi

Thanks for your reply

Pipe volume is in cubic meter

nitrogen volume is required in Us gallon

Pressure is psi

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#9
In reply to #7

Re: Nitrogen volume calculation

09/04/2014 9:44 AM

One cubic meter = 264.17 US gallons.

So ten cubic meter pipeline requires 2,641.7 US gallons of liquid nitrogen to fill. This is correct for 1 atmosphere and 30psi (both psig and psia).

As Crabtree stated, temperature may come into play here somewhere.

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#2

Re: Nitrogen volume calculation

09/03/2014 10:44 AM

A1) It depends on the throughput and the purge pass condition, which aren't stated.

A2) 44.7/14.7 times as much as A1 above.

A3) it depends on final temperature, which you haven't stated either.

A4) 44.7/14.7 times as much as A3 above.

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#3

Re: Nitrogen volume calculation

09/03/2014 11:09 AM

What are you actually trying to do? Why do you want to purge this pipe and nothing else? What is the significance of 30psi? If it were either 40 or 25psi would it matter?

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#4
In reply to #3

Re: Nitrogen volume calculation

09/03/2014 11:28 AM

"What are you actually trying to do?"

Get a passing grade on this class, I suspect.

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#5
In reply to #4

Re: Nitrogen volume calculation

09/03/2014 11:42 AM

Hahahahahahaha!

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#8
In reply to #3

Re: Nitrogen volume calculation

09/04/2014 9:44 AM

Hi Crabtree

Requirement of purging/lay up for commissioing. Pressure does not matter . I would like to calculate the volume in gallon for final pressure.

i have note this formula

The nitrogen volume required to purge equipment with a simple cross

section is determined using the following formula:

V = VoP/14.7

Where:

V = Total nitrogen volume required (scf)

Vo = Water volume of pipeline (cf)

P = Absolute pressure of nitrogen in the pipeline

during purging (psia)

Is it right?

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#10
In reply to #8

Re: Nitrogen volume calculation

09/08/2014 5:36 AM

If the pressure <...doesn't matter...> and there is nothing to say about the point when the purge criterion has been met then the volume required is certainly no greater than the volume of the pipe.

If the temperature is undefined as well, then the volume of liquid nitrogen to achieve the undefined volume will also be no greater than the volume of the pipe.

And that is all that can be said about that sorry state of affairs.

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#6

Re: Nitrogen Volume Calculation

09/03/2014 1:34 PM

A. 10 cubic meters.

B. 15 cubic meters.

C. 20 cubic meters.

D. 1 gallon per PSI.

E. 2 gallons per PSI.

F. 3 gallons per PSI.

G. All of the above.

H. None of the above.

How to calculate gas volumes | The Chemistry Journey | The

Ideal Gas Law Equations Formulas Calculator Volume

Chemistry Tutorial : Molar Gas Volume - Aus-e-Tute

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#11

Re: Nitrogen Volume Calculation

10/26/2014 1:20 PM

To calculate vol. of liquid N2 to fill 10 Cu. m of N2 at ambient temp. we proceed as follows:

22.4 M3 of any gas at NTP (1 atm. & 0 deg. C) weighs equal to its Mol. wt. in kg.

which means 10 M3 vol. of N2 at NTP weighs = (28/22.4)*10 = 12.5 kg

To calculate wt. at ambient (say 20 deg. C) the wt. will be less as per gas laws = 12.5*273/(273+20) = 11.65 kg

The density of liquid N2 = 0.807 = 0807 kg/litre

Vol. of liquid N2 required = 11.65/0.807 litres = 14.44 liters = 14.44/3.785 US gallons

= 3.815 US gallons

To calculate liquid N2 Vol. required at 30 psi proceed as follows:

Wt. of N2 at 30 psi as per gas laws = 11.65*30/14.3 = 24.44 kg = 24.44/0.807 = 30.28 litres = 30.28/3.785 US gallons = 8 gallons.

This could have been calculated directly as = 3.815*30/14.3 = 8.00 gallons.

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