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Participant

Join Date: Sep 2014
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Trapezoidal Rule Approximation

09/23/2014 11:08 PM

I am doing this problem where I have to do transient analysis using trapezoidal rule approximation. I am using a lumped parameter model.

___/\/\/\/\..../ ........................|....... 00000......|....................*

+ | 10 ohms t=0.0001 sec | inductor |

(vs) capacitor capacitor

| | |

Ground ground ground

How do I approach this problem.
How to reduce this circuit into norton equivalent?

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Guru

Join Date: Oct 2008
Posts: 42355
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#1

Re: Trapezoidal rule approximation

09/24/2014 12:11 AM

We don't do homework here, but

Trapezoidal rule (differential equations) - Wikipedia, the free ...

There are more if you search for them.

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Active Contributor

Join Date: Mar 2014
Posts: 20
#4
In reply to #1

Re: Trapezoidal rule approximation

09/25/2014 7:33 AM

I would suggest getting a different source than Wikipedia as this site is very loose on who can add/change things. Thus Wikipedia is a site that will never be referenced in any document.

Try to search google.

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Guru

Join Date: Sep 2012
Location: Iowa, USA
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#2

Re: Trapezoidal rule approximation

09/24/2014 4:16 AM

Are these the skills you've learned so far in making a circuit drawing and posting it, using your computer skills?

I am unable to decipher your question. Just what are you trying to solve. What will a Norton equivalent produce?

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Guru

Join Date: Apr 2014
Posts: 1869
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#3

Re: Trapezoidal rule approximation

09/24/2014 5:39 AM

What is the 'circuit?'

Please describe in words or sketch it out, take a pic of the sketch and post it. What you've 'drawn' thus far makes no sense at all.

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Guru

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#5

Re: Trapezoidal Rule Approximation

10/02/2014 12:42 AM

There are two methods of integral numerical approximations:

1) Method of inscribed trapezoid:

y(x+h)=y(x)+h*y'(x)+h^2/2*y"(x)

y'(x+h)=y'(x)+h*y"(x)

yn+1=yn+1/2*h*[f(xn,yn)+f(xn+h,yn+h*f(xn,yn)]

2)Method of circumscribed trapezoid

y(x+h)=y(x)+h*y'(x)+h^2/2*y"(x) then

y'*(x+1/2*h)=y'(x)+1/2*h*y"(x)

yn+1=yn+h*f[ xn+h/2,yn+h/2*f(xn,yn)]

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