You are at an empty playground on a hot day. You place your glass of water on the playground's merry-go-round (aka carousel or roundabout) and begin to spin it.
What happens first: does the glass slide off, does the glass fall and water spill, or does the water splash out of the glass?
What factors or principles are at play in your reasoning?
ANSWER, 6.26.23
There are 3 important factors at play. Kudos to those who identified all 3.
- How full the glass of water is.
- How 'slippery' the surface of the carousel is (i.e., friction)
- The shape of the glass, including its resting surface area.
As the carousel begins to slowly spin, first the centrifugal force will begin to increase the level of water on the outward side of the glass. It will begin to splash out, but only if the glass is (1) full enough and (2) of a shape that permits it. A glass with a convex lip, like a stemless wine glass, will retain water longer.
The carousel speeds up, and what occurs next depends on if the centrifugal force will can overcome the standing friction of the carousel surface and glass bottom. If yes, the glass will begin to slide until it falls off the edge. If no, the center of gravity of the water is likely to move far enough outward that the glass spills right on the carousel. Much depends on the carousel material; most are painted steel, making the sliding scenario most likely.
|
Comments rated to be Good Answers:
Comments rated to be "almost" Good Answers: