Re: (B.E.)(Electrical) testing engineer of transformer having more than two years ex
09/11/2007 11:32 AM
Vs/Vp=Ns/Np
you have 240v in your house, some of the lights are only 12v downlighters, so you need a transformer! If there are 1000 primery turns, how meny secondary turns would the transformer have?
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Re: Calculating Primary and Secondary Transformer Windings
09/12/2007 5:52 AM
The output amps will be determined by the load. The transformer has to be sized so as to accomodate the load current at the outpur voltage. Transformers are typically quoted as ??VA; this shows the maximum amount of power that the transformer can transform in the long term without deterioration or failure. Protection against overcurrent could be by fuses or overcurrent circuit breakers, for example.
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Re: Calculating Primary and Secondary Transformer Windings
09/11/2007 8:12 PM
I'm not sure what you're looking for, so here's a sort of long answer.
Assume a sinusoid voltage. For other shapes, you have to use a Fourier series or a "tried and true" formula.
The number of turns N = Vrms X 108/4.44BfAeff where B is the operating point of the core material in Gauss, f is the frequency in Hz, and Aeff is the effective cross-sectional area of the core.
B can be obtained from a magnetization curve for the core material. You need to stay below saturation and many people will develop a rule of thumb like 0.9 of saturation, or 0.85, depending on how they want to limit core losses and/or allow for over-voltage. The core manufacturer will supply those curves as well as loss curves.
The effective cross-sectional area is a function of how the core is made. In a powder core, you will need to consult the manufacturer's data sheet. For stamped laminations, you generally use a stacking factor that accounts for coating on the lamination and the slight burr produced by stamping which keeps laminations from lying perfectly coincident. The stacking factor will typically be in the 0.85 to 0.95 range, but that also depends on size.
Frequency is obvious.
Now, there will be a primary current which is proportional to the secondary current plus some current to cover losses (heat) in the core. There will be an IR drop from those currents and that will decrease the primary voltage slightly. I am greatly simplifying this explanation since you are starting out. Later, you can look at equivalent circuits.
Likewise on the secondary side, there will be some voltage loss. The result of this is that the ideal ratio Ns/Np will only be about 98% realized. If you are only, say, a freshman college student, you can probably just ignore all that loss stuff. If you are a working engineer, you need more detail.