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Cumulative Voltage Drop

10/09/2018 12:34 AM

Which is the correct equation for calculating the cumulative voltage drop?

For example, the power supply sequence is Transformer --> MDB --> SMDB ---> DP ---> LP ---> 1PHASE FINAL CIRCUIT

VD1 = 3 Phase voltage drop from transformer to MDB

VD2 = 3 Phase voltage drop from MDB to SMDB

VD3 = 3 Phase voltage drop from SMDB to DP

VD4 = 3 Phase voltage drop from DP to LP

VD5 = 1 Phase voltage drop from LP to FINAL CIRCUIT

Cumulative VD = VD1+VD2+VD3+VD4+VD5

(OR)

Cumulative VD = (VD1+VD2+VD3+VD4)/1.732 +VD5

If the second equation is correct, why do we have to divide the three phase voltage drops by 1.732?

Thanks!

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#1

Re: Cumulative voltage drop

10/09/2018 3:18 AM

It depends upon the installation's configuration, which has been withheld from the forum.

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#2

Re: Cumulative Voltage Drop

10/09/2018 10:06 AM

It depends on your circuit.

If your final single phase circuit is phase-to-neutral and you measure your voltages at the 3 phase points as phase-to-phase, then you divide the 3 phase voltage measurements by the square root of 3 (1.732...) to calculate the voltage drop you would have measured if you had been measuring phase-to-neutral at the 3 phase points.

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#4
In reply to #2

Re: Cumulative Voltage Drop

10/09/2018 3:14 PM

...though this assumes that there is no other load on the circuit. Without the original poster's circuit description, it is impossible to tell.

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#6
In reply to #4

Re: Cumulative Voltage Drop

10/09/2018 11:55 PM

There are other single phase lighting circuits.

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Guru
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#8
In reply to #6

Re: Cumulative Voltage Drop

10/11/2018 7:10 PM

<...single phase lighting circuits...>

3-phase lighting circuits are somewhat uncommon...

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#3

Re: Cumulative Voltage Drop

10/09/2018 11:07 AM

Your question has been answered on the IET forum.

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#5
In reply to #3

Re: Cumulative Voltage Drop

10/09/2018 5:52 PM

Thank goodness for that.

NEXT!

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#7

Re: Cumulative Voltage Drop

10/10/2018 3:58 PM

What's the point of adding all the drops? The sum of the drops is just the initial voltage minus the final one, correcting for whether it is phase-to-phase or phase-to-neutral of course.

You can, however, look at each individual IR drop to show where a possible trouble spot is.

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