Aluminum Disk Material

https://www.almecogroup.com/uploads/9297-ALMECO_vega_ENG_L101_03_2016_mail.pdf

appreciate the link, handy for the future, as present i am strictly concerned about the stability of a heat sink disk i am working with, doesn't need to reflect just conduct the heat away from my 10x10 100 watt led chip array, without warping at the slightest bump. any suggestions? measurement is: 9.5 " in diameter by 0,80 thick.

thanks don

I wouldn't think an 0.8 inch thick x 9.5 dia aluminum disk would warp. Aluminum is a good conductor of heat, so both sides would not differ that much in temperature.

Heat has to go somewhere, so for continuous use, heat sinks are usually finned to expose maximum area to convecting air. If your use is not continuous, a large block can absorb the heat for a short time.

To calculate how long:

The volume of the aluminum disk is 21.36 cu in or 350 cm³.

Aluminum density is 2.7 g/cm³ so the mass is 945 g. or 0.945 kg

Aluminum heat capacity is 897 J/kg deg C or 847 J /(.945 kg) deg C

1 Watt = 1 Joule/ sec

847 Watts will raise the heat sink 1 deg C per second

If you know the efficiency of your LED array, you can figure the heat dissipation (watts) and determine from the above how fast the disk will get hot.

You should have a good thermal connection between the LED chip arrays and the heatsink (heat sink grease or a thermal gasket) and a tight connection to the heat sink.

I hope this helps...

See: https://en.wikipedia.org/wiki/Heat_sink

Volume = π×4.75²×.8 = 56.705747397296 inches³

^{This doesn't sound right....surely this plate must be ribbed...}

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To design a heat sink you need to know how much heat is being generated, and determine the ambient operating temperature range...You must also take into account the free airflow available in the design of the fixture...So you need the efficiency of the LED's, the total wattage, contact area available, technical drawing of the light fixture...

Is this the type LED light...?

https://d114hh0cykhyb0.cloudfront.net/pdfs/ALD_High_Voltage_Series_Manual.pdf

If the problem is stability of the metal disk, it sounds like your disk is annealed and needs to be hardened to keep the desired shape. https://www.engineersedge.com/aluminum_tempers.htm If you don't have heat treatment facilities you can harden it up pretty quickly by hammering it all over. A light touch is best to retain as close as possible the original shape and thickness.

A description of more than 11 words might yield a more helpful answer.

20 questions is not much fun for those offering help.

Where have you searched so far?

"characteristics of aluminum disk material"is readily available by searching.

More detail=better answers.

Please state the basis of the input requested. The forum has only 11 words to go on so far, though the fact that none of them is a TLA is appreciated.

Although LED lights are considered more efficient than incandescent light bulbs, that is referring to luminous property...LED's produce a lot more heat per watt than incandescent bulbs....

..."The energy consumed by a 100-watt GLS incandescent bulb produces around 12% heat, 83% IR and only 5% visible light. In contrast, a typical LED might produce 15% visible light and 85% heat. Especially with high-power LED's, it is essential to remove this heat through efficient thermal management."..

https://www.calculatorsoup.com/calculators/conversions/power.php

https://www.quora.com/How-much-heat-is-generated-by-LED-light-bulbs

Unless that incandescent bulb is in an enclosed fixture.

I can't even put an LED in a clip on lamp with an open end... they really can't take the heat. Had a bulb explode before I learned that lesson.

I thought LEDs were more efficient than that. The 9 watt LED in my room seems to produce more light than the 60 watt incandescent it replaced. I thought (as a rough general approximation) an incandescent could be replaced by an HID of half the wattage, a fluorescent of 1/4 the wattage, or an LED of 1/8 the wattage. If the incandescent (100W) produces (in effect) 5 watts of visible and the LED 15 then only factor of 3, not 8.