Use of Cycloconverter for Resistive Load

Something like this?

https://www.electronicshub.org/cyclo-converters/

https://www.tandfonline.com/doi/abs/10.1080/00207218508939036?journalCode=tetn20

https://core.ac.uk/download/pdf/230490341.pdf

Why go to all the extra trouble to use a cycloconverter? For resistive heating you can just use voltage control much much simpler.

could you recommend on what type of voltage control and range?

Thanks

Research solid-state heater controllers; there are many manufacturers. As for range, no one can say until you tell us how many kW and how many phases.

You could probably go with something like this...

https://www.omega.com/en-us/control-monitoring/relays/solid-state-relays/p/SCR19

As written, this does not make sense to me. A cycloconverter steps down the frequency of a higher frequency source to be applied to a load. It does not change the load itself. It also does not change the peak voltage applied to the load. The load you specify, a resistive heater, has no frequency dependent factor so changing the frequency will have little to no effect.

AP,

You mention wanting to vary the load "by using the control firing angle", but then are talking about a "cycloconverter", which is a wrong name for the control you describe. I suspect you are talking about a single-phase or three-phase silicon controlled rectifier (SCR) or similar device which does not change the frequency but does change the firing angle of when during the sine wave the output is turned on. The various suggestions others have given appear to be what you were wanting.

--JMM

Please stop SHOUTING. Others here are trying to get some sleep.

Many heat load control applications use a simple thermostat. Why not here?

This is interesting topic, I am looking for similar application for a load bank, but I am using Thyristors (SCR) by controlling the voltage to get a different output power to the load bank. this will be on 120VAC input and varying the voltage with 25%, 50%, 75%, and 100%. this will be done by getting a fixed 3 ohm to get 5000W power and change the firing angle of the voltage to get a lower wattage.

does this make sense? any recommendation?

hmmm! let me try to figure out this

P=V^2/R = ie R = V^2/P = 120^2/5000 = 2.88 ohm ie ~ 3 ohm. okay that is the maximum power. and what is the minimum power? 500W?

for min. P = 500W, what is the resistance required, under full V

ie 120^2/500 = 28.8 ohm ie ~30 ohm okay

then figure out the rest

It sounds like another one of those exercises in pointlessness that an over-enthusiastic recent graduate might dream up - anonymously, of course.

<unsubscribes>

Agreed. Here is a generic synopsis:

Can somebody change <engineered system> to perform <other task> even though it is not designed to do this? Probably somebody can but since the OP has to ask I doubt they will succeed.

Good Luck

Have a nice day

Stay Safe