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Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 8:23 AM

I have heard that an open secondary CT at primary full load conditions may become dangerous as high secondary voltages are produced as there is no secondary back emf etc and may cause arcing and hence damage.Lets look at this technically

A CT is basically a step-up transformer(from voltage point of view).In the case of 400/1 A CT the primary turn is 1(say the busbar)and the secondary turns is 400.How much will be the primary voltage drop?? it will be in millivolts for a busbar.So this millivolts multiplied by 400 will cause just around a few volts (say 3 to 10V) for an open secondary.But i have read that the secondary voltage will reach a few kilovolts for a 400/1A CT at full load conditions.My question is how it will reach a few kilovolts and damage the CT on open secondary condition?As we have seen above the max voltage wil be just in few volts.So please someone correct me where i am wrong??

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#1

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 8:47 AM

I think you're asking about a 1:400 step-up transformer? If you have an open (or even lightly loaded) secondary, when you open the primary, you get a big voltage across that secondary. You have only to look at the coil and points on an older car.

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#2
In reply to #1

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 8:56 AM

Friend a CT basically steps down current at secondary side i.e it steps up voltage at the secondary.So it becomes a step up transformer as transformers are termed step-up or step-down if they are stepping up or stepping down voltage respectively.

I am talking about a 400/1A CT( the primary full load current = 400A & secondary current = 1 A) which is mounted on the bus-bars say of GIS in a substation.

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#3

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 9:25 AM

<...open secondary CT....may become dangerous as high secondary voltages are produced...>

Correct. For information, this is why circuits fed from a current transformer are not fitted with fuses.

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#6
In reply to #3

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 10:53 AM

Oh, CT = current ransformer. I thought Center Tap. Duh. I may need to visit my neuron (I keep it in a jar of single-malt at the National Aviary) more often than just on senior discount days.

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#13
In reply to #6

Re: Why an Open Secondary Circuit CT is Dangerous???

03/03/2010 8:16 AM

not correct ans dear

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#4

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 9:52 AM

You are thinking in voltage terms, these are current transformers, you need to think in current terms. Whilst current is circulating in the secondary it induces a back-emf which opposes the emf induced by the current in the busbar. When the back-emf fails because you don't believe it matters and have broken the circuit, the current in the primary takes on an unopposed magnetizing role, the magnetizing force (MMF) is I x N in ampere-turns.

you know Es/Ep = Ns/Np so Es = Ns/Np x Ep

If you substitute Ip x Rp for Ep (from Ohm's law) you have

Es = Ns/Np x Ip x Rp.

Putting your values in and assuming 100A in the primary with a resistance of 1 ohm

Es = 400/1 x 100 x 1 = 40000V, at 0.1 Ohm it's still 4000V

that's a bit bigger than your figure of 3 to 10V

It's been years since I did this, I think that's correct, if not others will point out the error.

The 16th Edition does not allow protective devices in CT secondaries for this reason.

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Anonymous Poster
#11
In reply to #4

Re: Why an Open Secondary Circuit CT is Dangerous???

12/02/2009 7:24 AM

The mistake in this argument is

Ip is only dependent upon Ep .i.e. Ep is not equal to the product of Ip x Rp .Even when there is no load on the primary,the EP will be there .

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#5

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 10:41 AM

Yes, I've just talked to someone cleverer than me (there are lots of those) and the last post didn't describe the process correctly. Transformer action couples impedance by matching current actions according to the turns ratio. Therefore as the current stops in the secondary due to infinite impedance that impedance is coupled back to the primary where it attempts to stop the current flowing, this will cause (most of) the applied (mains) voltage to appear across the primary which in turn induces a pro-rata step-up voltage in the secondary.

This implies 240V (say) x 400 = 96000 V in theory causing insulation breakdown and fire in the secondary. I hope this helps.

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#7

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 1:15 PM

HUX explained it quite well but a more simpler explanation is that a CT is a current transformer, which is different to a standard voltage transformer (VT).

VT's don't like to be shorted out (output voltage tends to 0 as current gets really big, VT heats up and is damaged). CT's on the other hand are designed to work differently, shorting the output is not a problem as they work with current and current is what you are measuring (the output current stays at a reasonable level and mirrors the primary current, in your case 0.25A for every 100A of primary current). Iif you open-circuit the output the voltage will increase to try and keep the circuit (and the secondary current) going and it will keep increasing to a very high level. This is why CT's are fitted with shorting links and test blocks so that the secondary is never open-circuited when current is running thru the primary (which is very capable of producing a large enough voltage to kill).

It's a fairly simple explanation (no magnetic field theory or calculations) but it may help to give you a better idea.

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#8
In reply to #7

Re: Why an Open Secondary Circuit CT is Dangerous???

01/31/2008 11:41 PM

Good explanation.

It is definitely true, we've had to rescue the same bloke from CT terminals twice.

I've seen where open circuited secondaries arced their way around and eventually through terminal insulation.

I've seen where intermittent open circuits in even small CT secondary leads have blown up electronic circuits in a big way.

Remember it is all about Ampere turns, when the turns can't push the Amperes through the burden resistor due to high resistance or open circuit the voltage must rise.

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#9

Re: Why an Open Secondary Circuit CT is Dangerous???

02/01/2008 12:24 AM

Not to get too far off topic, but for those who don't understand there is a more real danger of the current in an open secondary on a CT. Many CT's for industry are rated at 2.5VA or higher, which is more than enough current to stop the old ticker if you suddenly become the load for an opened secondary. For this reason, we put warning labels on all of our CT's. The voltage is almost a secondary danger in comparison of imminent lethality.

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#10

Re: Why an Open Secondary Circuit CT is Dangerous???

02/01/2008 9:36 AM

It is true that the construction of a CT makes it look like a simple step up VT and the difference is in the usage. In a CT the primary voltage drop is determined by the secondary voltage drop into the load. In transformer applications the secondary load is reflected to the primary as Zpri = Zsec * (Np/Ns)^2. So, a 50 ohm terminated 1 : 400 CT loads the primary coil with 0.313 milliohm. Higher output impedance (your fingers for example) will present a higher impedance on the primary allowing for higher voltage drops on both sides. The primary impedance will be limited by the transformer coupling and the primary inductance regardless of the secondary load impedance. In short you can get a pretty high voltage at the secondary.

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Anonymous Poster
#12

Re: Why an Open Secondary Circuit CT is Dangerous???

12/13/2009 9:44 PM

Voltage & current are relative to each other (Ohms law). If you have a CT that is a 400/1 ratio 400A on the primary side will only produce 1A on the secondary side. If your current is devided by 400 then your voltage must be multiplied by 400, hence giving you a dangerously high voltage if no burden is conected

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Anonymous Poster
#14

Re: Why an Open Secondary Circuit CT is Dangerous???

12/12/2010 11:49 PM

Ohm's law E=IR. Open circuit on secondary can be thought of as infinite impedance, R, thus E rises in proportion.

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#15

Re: Why an Open Secondary Circuit CT is Dangerous???

05/16/2013 1:21 PM

Dear Mr junaid,

The voltage is multiplied by the Ratio of C.T. In your case Primary Current is 400 Amps. and Secondary Current is 1 Amp. Hence Ratio 400/1 = 400, and there fore Voltage on primary side will be multiplied by 400 times, and hence open circuit on secondary is DANGEROUS.

DHAYANANDHAN.S

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