Agitation Power

So much depends on the agitator design (blade shape, pitch, count, etc...) that it is really hard to say. If you can identify the agitator's manufacturer, they would be best able to give you advice. The speed at which you wish to turn the agitator will matter as well.

If you cannot get any information from the manufacturer, you have two options: practical and empirical.

The practical solution is to take your best guess and triple the size of the motor. Install with a VFD to regulate speed and give 'er a go.

The empirical solution would be to fill the tank and try to measure the torque (big-a$$ torque-wrench?) required to just make the agitator move. Even better, try to measure the torque at approximately the speed you want the agitator to move. Knowing torque and speed will allow you to compute HP. Purchase 30% larger motor and install.

JFERREYRA;

I do have a excel spread sheet that have these.

you would need to know product properties.

you would have options for type of agitators and such.

I have'nt used them is quite some time. Please give me time to dig the up.

phoenix911

http://www.pdhonline.org/courses/k103/k103Content.pdf

thank you both for your replies.

(i'll wait the excel spread sheet.)

Hello JFERREYRA:

http://www.convert-me.com/en/convert/power#kilowatt

I have included this conversion calculator which may make things a little easier.

1 KW = 1.34 HP

Can you say the Fin size, rpm, Rotor Length/Tank Height, Please?

From the size of the tank are you mixing slurry at an effluent plant?

Is it direct drive or used with a reduction gear?

Or is it just for general 'rule of thumb' in calculating this motor size?

Just trying to help OK?

Take care and happy holiday..............

Hello BABYBEAR:
What I was looking last week, was as it is called, a "rule of thumb" to estimate preliminarly the power of a motor drive for an agitator.

Some information about our application:

1. It is an agitator with a reducer, not directly driven.
2. The speed of the agitator is about 16 / 20 RPM.
3. Fin size and model is not yet been defined.
4. Tank is 11.5 m height.

Thank you for your help,

happy holidays for you too....

Hello JFERREYRA:

Thank you for the reply post.................

These are what is going to help choosing the blades.

You already know the tank width and height.

You know how viscous the liquid is.

You have worked out what speed you need. (obviously, with a paddle that large is is going to be effective at relatively low speeds).

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You need to know the length of the spindle. This will help with the torque conversion.

You know what you are using this for but have not mentioned it on here.

I suggest you find another application which has a similar sized tank, and whose liquid is going to be the same temperature and density.

I am still looking but off the top of my head, I would not know what sized paddle to use. Find a similar application and see what size it uses?

You will need to know the paddle size, spindle length and required speed, and perhaps things I have not thought of to work out the paddle size. But, again this depend on whether the paddle blades will be fully submerged or only half submerged.

Your application is not very large, on 'industry standards at least. I would have thought a call or email to a paddle maker may help? Then once you know the size and other details like pitch etc, you can 'work backwards' to figure out the loads and stresses that are applied?

Can you tell me why you want to use this for? And have you done any searching yourself? And what exactly are your search terms?

Take care, and happy holiday..............

By doing pilot-scale trials. Open a dialogue with (an) agitator equipment manufacturer(s).

Telephone?