Converting Volume into Area

Here are some tables that may get you pointed in the right direction:

http://www.leatherchemists.org/conversion_table.asp

http://www.duncanrogers.com/tools/conversion.php

Don't know if they will help but good luck.

Well, you can't convert volume to area except by dividing by one of the dimensions.

I think your software has a bug in it.

I don't have much hope but this might help:

volume = area × height

So, if you can figure out what height you can work in, the area will present itself.

regards,

Vulcan

Call the vendor: your software is defective. Unless you're talking about population density, concentration is ALWAYS measured in mass/volume.

Hi I am Amit...I hope this is helpful to you. I use this and keep it on my desktop as quick conversion tool....download free from this link http://joshmadison.com/article/convert-for-windows/

Since volume is length x width x height, make one of your factors 1 and then area and volume are the same. So if you're figures are in cubic feet, convert to 12 inches by 12 inches by 1 inch. Result is 144 square inches and cubic inches (1/12th of a cubic foot).

Maria, it sounds like the same problem from my agricultural analysis background with USDA, where we determined the concentration of the species of interest in a water extract from a soil sample in ppm and reported it in either lb per acre or kg per hectare. The key was in the depth of the soil sampled. 1 acre-foot of soil weighs 4 million pounds. A 6-inch sample depth on the same area weighs 2 million pounds. So for soil samples, multiply the ppm by the appropriate bulk density factor, (2 or 4) to report lb per acre. Or make the simple conversions to report kg per hectare. This only works because most scientists in the field understand that the third dimension (depth) is set constant. In your paper you must report the actual depth sampled or your reviewers will let you know about it.

If you are doing pollutant analysis on a solid sample from which a weighed subsample has been subjected to an extraction process with a known volume of solvent, you need the bulk density of the material sampled. Then you need a protocol that isolates one dimension.

If you are testing surface water samples, you need additional data to relate the volume of runoff to the area from which it came.

Hi, well as your work at the USDA you should know or heard about the CityGreen (from the american forest www.americanforests.org). In order for the city green to run the analysys all the units should be in g/m2. But I created all my data bases with my data and it was in those units...

I will check what you wrote and tell you how it worked..

Thanks!!

hi Maria,

could it be possible that the software is asking for an entirely different thing? perhaps the area of the room, or space where these pollutants are found?

just a hunch.

For a rough calculation I think you can divide the room volume with the height.

Hi, Maria.

Unlike the others, My guess is that the soft"ware is prompting you for the area of the sample capture media (filter) so so many grams per unit area of sample filter is the possibility I suspect.

By not describing how you took the samples, not knowing that you probably using a pump that collects and captures on a filter, what you describe makes no sense. But if the software expects the filter to be certain area, and based on a certain time of sampling, the software will likely then calculate the volume.

I also suspect it will take your final weight, and then figuring the standard pre test weight, calculate based on the difference automatically.

Thats my conjecture, having used pump type samplers before for industrial hygiene work.

hope this helps.

milo