KWH

T:

KWH = ∫VI CosΦ /1000 dt where V,I,Φ are f(t)

or if simple (inaccurate form)

= tVI CosΦ

t in hrs, V amd I in Volts and amperes resepectively.

(not 1/cosΦ)

and also efficiency does not matter since we are not concerned with the output mechanical/other powers

Oops, I'm sorry--I forgot the 1000 factor for KW vs. W!

For "normal" AC loads, cos φ is the same as power factor (although power factor can be more complicated depending on wave form).

That was a GA, so I will partly cancel the self-imposed OT. Thanks for catching my mistake!

We old timers do not want to unnecessarily catch others slippage . I do it once in a while and since the question was too elementary even for Dr Watson so the mistake correction on post, i didn't feel necessary.

Even my children understand what is the unit, and how it can be calculated. Of course they are too young to be taught about the √3 or cosΦ, only conceptually.

And with so many posts on KW, KVA , Pf and KW or KVA I sometimes feel like screaming when I see a post on it again .

I may resort to a deliberate wrong answer or may be far better I will provide a differential equation using fourier to solve, that will be of course not wrong, but fun.

Well, in that case you probably could really pick me apart! I am by no means a high-level theorist, but I have a notion of Fourier analysis, FFTs, and the like. I'm more of a hands-on type with electrical, hydraulic, and piping experience, with the occasional step up into moderate theory. On CR4 I'm sometimes a prankster, but mostly I try to give ideas that are technically sound at a conceptual level or so. Once in a while I goof, but for the most part I hope I have found a decent balance.