Another Number Riddle

Aaaaarrrrrggh!

Hi Blink,

Is it 363?

Mike

No, not 363.

Should be 342.

jhunter

No, not 342, although it would be interesting to know how you came up with that.

I think most engineering types would not require a calculator to figure this out. It may be more basic than people realize. A related concept is used in adding 129 and 291 to get 420.

275?

No, at least not in my simple scheme.

Here's a hint: the seventh number in the series (the one just after the one we are looking for) is 1023.

Here's another hint, maybe.

Just a minute ago, I found a website that would make coming up the the numbers in this series very very fast. The only problem is that if you knew where to look for the website, then you would have already figured the riddle concept... at which point the website would be somewhat superfluous.

Gee, that helps

Well, here's another hint. The element of the series just before the first one I gave (75) would be 69. Another hint: If I gave you the 9th element in the series, the concept would be much more obvious.

Circa 5:30 pm eastern time today, I'll spill the beans, so there is not much time left to garner big money, fame, and fortune.

This is the ninth number, which should pretty well give you the answer to the other numbers.

1001011

As I said, quite basic...

I'm back for a sec, is the 6th number 297?

jhunter

No, but that is close, in one way.

The ninth number has a distinctive appearance, having only ones and zeros.

The number that would come three before the first number (75) would be 5A.

Blink I know its so simple but you are driving me mad! LoL

I'll try again.

jhunter

Me too!

I'm trying to watch a movie and I can't with this on my mind!

Mike

OK, OK, OK.

1001011 is 75 in binary.

So the numbers are all theoretically equal to 75... first in base 10 , then base 9, then base 8, base 7, base 6, base 5 (300), etc.

HOWEVER, the nut case who put this together somehow put down 93 instead of 113 for base 8... which I just noticed a few seconds ago, as I wrote the sentence above (which I then had to rewrite). Arrrrrghhh.!!.

Let's see, how do I back out of this gracefully.... Oh yeh... I meant to do that , and intended to put in, as part of the challenge "Find the mistake in this."

Please don't break my arms!

We wont break your arms as long as you give us another one in the future to try.

jhunter

Ahem! 6th graders understand the concept of number bases? I don't think I was even introduced to it until I was in high school!

!

Excellent! GA

Ok, here's one for you:

000,001,011,010,110,111, what are the next 2 (or more) numbers in the sequence?

-HTRN

101 then 100?

jhunter

I was thinking 101 and 1000 (but I reserve the right to be completely wrong)

Mike

I was thinking that as a possiblty but then it looked like he just reversed the order which followed out would be 101, 100 and then possibly start over with 200. I may be way off.

jhunter

Try again

sorry! no.

nope

1000 then 1001

OK, here's one:

0011, 0001, 0100, 0001, 0101, 1001, ___, ____ ?

Mike

0010, 0110, 0101 ...

OK - too easy.

For the original problem, the 10th number would be 000...000 (75 zeroes). Then, skipping zero as a base, you get into negative integer bases....

238

Ok I am encouraged to post one too....here is one: 1, 2, 3, 4, 5, 6, 7, 8....

Now guess whats the next one....hehehehe

In base 9, it would be 10, but other gimmicks could apply....

It is :

...... ,913,957

Sorry I'm late to this party: but, shouldn't 93 be 113?

Blink fessed up.....grab a pitchfork and join the hunt

I would set the first ten numbers of the sequence as:

Is this correct? I did not use binary to solve it.

297 perhaps!!!