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farmatt
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Area of an Angle Cut

06/17/2010 11:15 AM

Am having trouble remembering my college classes. Has been too long.

Need to find the area in square inches of the face left from cutting a solid (round) shaft at a 45 degree angle. For some reason, I am coming up with a different dimension each time.

Just the formula would be fine.

Thanks to all who can help

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Pathfinder Tags: angle area
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#1

Re: Area of an angle cut

06/17/2010 12:14 PM

Transverse area/cos(angle)

In your case pi*d^2/4/cos45°. When the angle =0 then cos(angle)=1.

1/cos45]=1.4142 (= sqrt(2))
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tdesmit
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#2

Re: Area of an angle cut

06/17/2010 12:19 PM

Should just be the area of an ellipse, shouldn't it?

Pi x R1 X R2

R2 would be the radius of your shaft, R1 would be 1/2 the distance of the hypotenuse of a right triangle with sides of the diameter of the shaft. Sorry, my math skills are so rusty, I don't know how to express that a formula :(

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Randall
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#3

Re: Area of an Angle Cut

06/17/2010 1:22 PM

Both answers so far are correct:-

Πr2√2

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#5
In reply to #3

Re: Area of an Angle Cut

06/17/2010 2:43 PM

But what if the angle wasn't 45°?
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Randall
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#6
In reply to #5

Re: Area of an Angle Cut

06/17/2010 3:17 PM

Then the Area is ΠRRcut

Where Rcut = R/Cos(ß)

But, he said the angle was 45°

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farmatt
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#7
In reply to #6

Re: Area of an Angle Cut

06/17/2010 3:33 PM

If they would let me, I would give you 2 GA's for this one

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Doorman
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#8
In reply to #6

Re: Area of an Angle Cut

06/17/2010 3:43 PM

Hello Randall.

Should not angle β be the included angle?

Or am I looking at your drawing upside down / inside out / crosseyed?

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Randall
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#9
In reply to #8

Re: Area of an Angle Cut

06/18/2010 2:16 AM

.

ß=ß (I know this sounds stupid but you know what I mean)

Cos(ß) = R/Rcut

So Rcut = R/Cos(ß)

Or am I looking at your drawing upside down / inside out / crosseyed?

Perhaps just a "Floydian slip".

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Doorman
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#10
In reply to #9

Re: Area of an Angle Cut

06/18/2010 7:08 AM

Ah.

More better. Thanks, Randall.

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farmatt
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#4

Re: Area of an Angle Cut

06/17/2010 2:43 PM

You all gave me good answers!

Thank you very much.

I gave each of you a GA

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farmatt
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#11

Re: Area of an Angle Cut

06/18/2010 4:02 PM

ALL of you that replied to this post were a big help.

Was attempting to figure the amount of pressure that was applied to the floor by a machine that was held up by legs made of shaft cut at a 45 degree angle where the legs met the floor.

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