Transmitter Calibration

Well, 4mA = 0%, 8mA = 25%, 12mA = 50%, 16mA = 75% and 20mA = 100%. Does that help?

thanks,in 0,25,50,75,100% how i can divide the pressure ranges,span =26

Wow.

Do you, as well as another questioner today, have a pet cuckoo bird? Will none of your classmates share their notes with you?

Instrument Zero = 4 mA

Instrument Span = 20 mA - 4 mA = 16 mA

Process Zero = -1 Bar

Process Span = 25 Bar - (-1 Bar) = 26 Bar

26 Bar / 4 = 6.5 Bar Decrements

4 mA = -1 Bar

8 mA = (-1 Bar) + (6.5 Bar) = 5.5 Bar

I'll leave it up to you to figure out the last three.

What a giveaway....

please give me full answer,i am fresh in instrumentation

No, I'm not going to do that. If you know basic arithmetic, and have elementary reasoning ability, you will be able to do it. If, on the other hand, you do not have these requisites, you should not be in instrumentation.

Are you going to have to ask someone how to do your job every time a simple problem comes along?

Think the problem through!

thanks,for 12 ma =12,16 ma=18.5and 20 mA=25,is it correct.

you are very correct..

<sigh>

I see you have already discussed with some other members with this thread.

And just what is -1 bar? Isn't a perfect vacuum zero barg?

0 bara or -1barg perhaps......

Ooops! Am I mixing it up?

1 barg ≈ 1 atm ≈ 14.5 PSI

0 barg ≈ 0 atm ≈ 0 PSI

1 bara ≈ 0 atm ≈ 0 PSI

I should probably check before posting this... throw caution to the wind.

[edit: I see you got a GA already; I must have it mixed up. I better check]

I wonder if the guest is lost, can't find the way back to his/her previous two threads, and therefore keeps asking the same question (or almost).