About Rectifier

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shaik.thameem Associate Join Date: Dec 2008 Posts: 33	About Rectifier 03/18/2011 2:28 AM
	Dear sir, i made one rectifier bridge (IN4007 diodes) and connect parallel one resistor(10K)and capacitor (470uf) and then measured rectifier bridge out put by giving input 0 to 15 VAC to bridge i got DC voltage according to formula (Vdc=0.90063*Vrms) up to 8VAC after that i didnt get correct output values[voltage increased after 8VAC].why it is so?please tell me. is there any good method to get correct values?please tell me sir thanking you
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rcapper Guru Join Date: Dec 2005 Location: Etats Unis Posts: 1871 Good Answers: 45	#1 Re: About Rectifier 03/18/2011 10:45 PM
	With a light load the correct peak voltage is VAC RMS * 1.414214 (the square root of 2). Not sure where you got 0.90063. __________________ The hardest thing to overcome, is not knowing that you don't know.
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aurizon Guru Join Date: Jun 2006 Location: Toronto Posts: 3968 Good Answers: 120	#2 Re: About Rectifier 03/18/2011 11:17 PM
	what rcapper says is correct, however, you have a slight load to discharge the capacitor, and so the cap willnot charge to the RMS peak of 15 volts (21.2 volts), instead it will charge tothe peak minus two diode forward voltage drops of 0.7 volts each = 1.4 V. thus at 15 volts and just the 10K load you will see 21.2 - 1.4 = 19.8 Volts. As you ramp down to zero, the same relationship will follow, except when your AC drive drops below a peak voltage of 1.4 volts, when none will pass. __________________ Per Ardua Ad Astra
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ashoktoshniwal Power-User Join Date: Aug 2006 Posts: 183 Good Answers: 2	#3 Re: About Rectifier 03/19/2011 1:56 AM
	Output DC might still contain some ripple and therefore DC output if measured in DC range will not give exact DC value.Try measuring using True r.m.s. multimeter.
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