A good analogy which applies to FETs (field effect transistors) is to imagine a soft hosepipe with water flowing through it, by applying a small variation in pressure to pinch the pipe you can control a big flow of water.
Del
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health warning: These posts may contain traces of nut.
Do also check out the Wikipedia pages on this topic.
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"Did you get my e-mail?" - "The biggest problem in communication is the illusion that it has taken place" - George Bernard Shaw, 1856
A transistor has three leads, two of which can carry a lot of
current, and a third leg which I call the "signal lead". The other two
leads have an inlet side (which never changes voltage) and an outlet
side whose voltage goes up and down according to what the signal lead
tells it to do.
A small change of voltage on the signal lead of the transistor will
cause a greater or lesser resistance to be created between the other two
leads. That changing resistance will result in a changing voltage drop
at the outlet. The amount of voltage drop will vary directly with the
applied voltage to the signal lead. That big voltage drop which exactly mirrors
the tiny applied voltage is what we call "amplification".
You can never get a higher voltage at the output of the transistor than what you apply to the inlet side.
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This was an exercise on my part. It has been years. Anybody think it was too simplified?
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If it was easy anybody could do it.