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Anguraj Chelladurai
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Status of current in voltage divider circuit

11/25/2011 3:58 AM

Can anyone clarify my doubt...!

The question is, When a load resistance is removed from the output of a voltage divider circuit, the current drawn from the source..........?

a) decreaes

b) increases

c) remains the same

d) is cut off

I need exact answer...

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Tornado
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#1

Re: Status of current in voltage divider circuit

11/25/2011 4:47 AM

This is a poorly written test question; the phrase "When a load resistance is removed" is too vague.

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Anguraj Chelladurai
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#2
In reply to #1

Re: Status of current in voltage divider circuit

11/25/2011 5:01 AM

Here, load resistance refers to resistance connected at the place of load portion of the voltage divider..?

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electronick
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#3
In reply to #2

Re: Status of current in voltage divider circuit

11/25/2011 5:33 AM

depends on the resistence

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PWSlack
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#4

Re: Status of current in voltage divider circuit

11/25/2011 6:57 AM

<...need exact answer...>

The forum needs a circuit diagram for that.

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JRaef
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#5

Re: Status of current in voltage divider circuit

11/25/2011 1:21 PM

Scan the appropriate page of your textbook and post it for us.

Oh wait, that would entail that you ACTUALLY READ your textbook, and by virtue of the fact that you are trying to get other people to do your homework for you, that is not likely to happen...

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Anguraj Chelladurai
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#8
In reply to #5

Re: Status of current in voltage divider circuit

11/27/2011 11:28 PM

Its not my home work... I had doubt that, If the load resistance is removed from the voltage divider means, from the source, the status of the current will be whether decrease or cut-off..

The answer is given as decrease.. But, my question is, how it will be like that.. By removing the load resistance refers to opening the circuit... So, definitely current drawn from the source should be cut-off.

I got this question from

http://indiabix.com/electrical-engineering/series-parallel-circuits/113003

Please reply to this..

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wareagle
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#6

Re: Status of current in voltage divider circuit

11/25/2011 7:42 PM

e. can not be answered
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Tornado
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#7

Re: Status of current in voltage divider circuit

11/25/2011 7:50 PM

f. none of the above.
g. some of the above.
h. all of the above.

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PeterT
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#9

Re: Status of current in voltage divider circuit

11/29/2011 11:48 AM

This doesn't seem like anything more than a basic circuits question to me. Wish I could post a sketch - it would make it easier. Assume a voltage source V feeding a voltage divider R1 and R2, with the load RL connected across R2 of the divider. Current in the circuit is then simply I = V / (R1 + (R2 || RL)). Since R2 and RL are in parallel, the combined resistance is less than R2 alone. Therefore if you remove RL, the current is V / (R1 + R2). Since the total resistance increases, the current decreases, and the answer is a) decreases. What's so hard about that?

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Anguraj Chelladurai
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#10
In reply to #9

Re: Status of current in voltage divider circuit

11/29/2011 11:05 PM

Thank you very much...

I have been satisfied by your answer...

Thank you..

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electronick
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#11
In reply to #9

Re: Status of current in voltage divider circuit

12/12/2011 10:57 AM

good question to refresh oldie problems !!! - that is in linear resistances and/or in cases were the parallel does not cause a unbalance on the circuit... there are tricky cases in some circuits

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Anguraj Chelladurai (3); electronick (2); JRaef (1); PeterT (1); PWSlack (1); Tornado (2); wareagle (1)

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