Can We Solve This Question by Mesh?

What's a Mesh?

Well, here's another nice mesh you've gotten me into!

Yes, it can be solved by mesh analysis. Now go do your homework or at least explain to us why you do not see how to solve this with mesh analysis.

Yes. Fig a reduces to Fig b reduces to Fig c. Calculate I1. Then go in reverse.

In Fig b you know what I1 is. Then determine what the other current are. You eventually get to Fig d.

Lyn

mesh = loop. You know it. Us older guys call it loop currents. http://www.allaboutcircuits.com/vol_1/chpt_10/3.html

There is a prior CR4 thread on this same problem. (Maybe with different numbers, but the method is the same.)

And also a Newsletter Challenge on an infinite variation of it:

A_ _ __. _ _ _...
B_|_|_|_|_|_...

where every line segment is the same resistance, say 3Ω, in this infinite "ladder"; what is the resistance between A and B?

Tornado

I vaguely recall seeing that problem. Did the answer approach zero?

@lyn

very very difficult question sorry i cant answer it

Tornado quote

"There is a prior CR4 thread on this same problem. (Maybe with different numbers, but the method is the same.) And also a Newsletter Challenge on an infinite variation of i:

A_ _ __. _ _ _...
B_|_|_|_|_|_...

where every line segment is the same resistance, say 3Ω, in this infinite "ladder"; what is the resistance between A and B?"

1/Req = 1/r1 + 1/r2 + 1/r3 + 1/rn r = 3 ohms

If all of the resistances are equal then

1/Req = N/r N = total of the number of resistors and r = 3 ohms

so 1/Req = N/r

Req = r/N

If N = ∞ then Req = 0

Any takers?

Every line segment both horizontal and vertical) contains a 3Ω resistance. Thus the total resistance includes 6Ω (the segments ending at A and B) plus the resistance of the remaining network. This can be taken as a hint that enables the construction of a quadratic equation.

That is a different problem.