Calculation of Pressure Versus High Water Column

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How to calculate the pressure in a water column - WikiAnswers

It just adds up doesn't it?

> it just adds up, doesn't it?

sum times

1 psi ≡ 2.31 feet

That stuff is O-level Physics - variaton of pressure with depth, that sort of thing.

Not clear what you're asking. As #5, calculating (static) pressure from water column is elementary physics, but that doesn't give you actual pressures at pump suction and discharge, you need to allow for pipe friction.

Is there just one set-up here, with system standing pressure (water column) 2.0kg/cm² and pressure of suction 1.2kg/cm² (the difference being friction loss) or are you trying to work out change in performance if suction pressure changes?

What do you mean by pump head, is this generated head?

• I wants to know any formula / thumb rule to calculate the pump head. what will the head of pump, if it is running with 1.2 kg/cm² suction and 3.4 kg/cm² discharge pressure.
• what will the pressure at bottom of 10 mtr high water column.
• how to find / guess / the suction pressure of pump before start. If any pump of 25 mtr head is equiped in inclosed circuit and circuit is having 2.0kg/cm² standing pressure.

• I wants to know any formula / thumb rule to calculate the pump head. what will the head of pump, if it is running with 1.2 kg/cm² suction and 3.4 kg/cm² discharge pressure.

That's just a repeat of your original post. Need answers to my questions to try to help

• what will the pressure at bottom of 10 mtr high water column.

Elementary physics, but if you can't do that, it's 1 barg near enough, if everything's static and open to the atmosphere

• how to find / guess / the suction pressure of pump before start. If any pump of 25 mtr head is equiped in inclosed circuit and circuit is having 2.0kg/cm² standing pressure.

First time you've mentioned closed circuit, is it a heating system? For a closed circuit you need either a header tank or an expansion vessel, to cater for water expansion (even if it's not a heating system). The connection to the header tank or an expansion vessel should be close to the pump suction, so that is the point of minimum pressure. The header tank should be high enough to provide pump NPSHR plus a margin (or expansion vessel pre-charge to provide it). The pump does not see any static differential head, only friction. Other than that you need to give more detail.

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Hi,

25 m head = 2.5 bar approximately.

Hi dspataw

http://joshmadison.com/convert-for-windows/

This is a free program, but I note under "Pressure" it doesn't have a direct conversion from water head in feet to PSI or m to Kpa. You can program this in yourself. 1m head = 10.19Kpa. Tony

It doesn't have a direct conversion from water head in feet to PSI or m to kPa because they don't have the same units. Pressure = h*ρ*g (in consistent units, extra factor otherwise) so density ρ is needed, and the calculator doesn't have the facility. Also g, but that's usually taken as constant.

But I'm not sure the OP is only asking for head to pressure conversion, he seems to want somebody to analyse his system.

Yes you are correct, I've spent too much time with water to realise there are are densities. Anyhow the the calulators good isn't it and I hope g continues to stay constant (stupid bloody newtons). Tony