How Do You Find the Max Allowable Stress in Tension of a Material

by testing it to verify your calculations

OMG! I pity us all, if you are an example of the future generations.

A search engine produced "About 13,500 results (0.27 seconds".

Read a book. Use a search engine. Ask the instructor. Ask a fellow student.

From the FAQ's, which you didn't bother to read: Look for answers before you post. Search CR4 or use a search engine to see if you can find the answer to your question.

Do your own homework. CR4 is not a homework cheat site; however, if you have questions about understanding concepts or how a portion of a problem is derived, these types of questions will be accepted.

Maybe this is how kids do homework these days.....just ask someone for the answer.

It is a real shame that these kids such as undergrad_mech are so lost that they don't even know what they are doing.

"of a material called X5CrNi18-10" leads one to believe that this lost soul doesn't even know what they are working with.

Undergrad mech indeed.

Youth is wasted on the young!

Stretch it until it breaks. Divide the maximum stress by 4 (or other code-mandated factor).

Easy. Put a test specimen in the post to Fredski, as in #1 above, so as to make use of that piece of equipment.

X5CrNi18-10 nearest UNS specification material is S30400. Maximum allowable stressis 138 MPa at temperature between -30 degree C to 40 degree C. As the temperature increases, the allowable stress decreases. So you have to specify a temperature to get correct value. The above data is in accordance with ASME Section IIP-D Table 5A.

You're question is ambiguous. Are you asking how to physically determine what the max stresses are or are you asking where you can find these value as in a document of some sort?