How Much Power Transmission In Belt Pulleys?

More or less. The bicycle chain drive is slightly better than the belt drive.

I cant agree more. That is because belts slip and have higher energy losses, while chain sprockets do not slip, and therefore more efficient. No wonder we have chain sprockets for bicycles rather than the belt pulley system.

The belt should not be very tight or very loose,alignment & selection of belt,pulley sizes,distance between pulleys too is important,refer manufacturers literature.

100% of the power that is transfered is transfered.

Lyn, I found out that in Vee belts, the wedging profile (trapezium) shape wedges into the V's of the pulley for friction to make the belt pulley system work. When friction is involved, this means that heat losses due to friction occur. Hence, the power transferred from the driving pulley to the driven pulley will be less efficient. And when there is slip, the angular speed and torque decrease as well.

Yes, to friction losses and slippage.

Since we have no idea of the many factors that may influence power transmission losses or efficiency, in your case, it's hard to answer in any detail.

Do you have a specific application in mind, or is this a theoretical question?

This is just a theoretical question. I would like to recite the principle that ideal power transmission is where power is transmitted to another shaft or direction, with variable rotational speeds and torques, yet power is maintained.

However due to losses due to heat/friction and other factors, power output is in reality lower than the source driving power transmitter.

I would think that there would be many scholarly articles on the internet.

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Lyn, appreciate discussion with you. Will venture to view and read more information as per advised.

snowmobiles are driven in this way.

Try this link: http://adventure.howstuffworks.com/outdoor-activities/snow-sports/snowmobile1.htm

Try this:

http://www.michaelsenergy.com/PDFs/energy_loss_and_belt_efficiency.pdf

V-belts 95-96%; flat belts ~98%, but they require higher tension and possibly heavier bearings.

When we discuss that there will be higher bearing loads, are you reffering to the radial and axial loads? Does that mean the most suitable bearing would be a ball bearing?

Radial; where would axial loads come from? Bearings would probably be ball or roller type.

Tornado, surely you are right. Radial forces will act. I just mentioned axial without concrete evidence. If I were relating to an application, maybe axial forces would also be considered. Thanks

You have to get losses and a 95% power transfer seems about right. The belt will get hot and hot is losses. Consider a belt 1metre long and a belt 1 mile long. I suspect the larger belt will take more to drive - there will be losses. Consider the route the belt takes. A nice circular route is one thig but these curious serpentine belts they use on cars where they go through a complicated route and use both sides of the belt - has to more losses.