I am wondering how to add HP of Hydraulic Pumps. If I have a pump and I wanted to calculate the HP needed to do the work required I would use this equation.
Horsepower input = GPM*PSI/(1714 * overall Eff)= HP
If I have a tandem pump ( two outlets and two inlets same shaft) one section at .714 CID (350 PSI 2800 rpm) and the other section at .144 CID (2000 PSI 2800 RPM). what would the pump HP needed?
Based on the equations:
.714 CID ==> 8.6 GPM (2800 RPM)
.144 CID ==> 1.74 GPM (2800RPM)
.714 HP ==> (8.6 GPM)(350 PSI)/(1714 * .85 eff)= 2.06 HP Assuming 85 % eff on Gear pump
.144 HP ==> (1.74 GPM)(2000PSI)/(1714*.85 eff)= 2.388 HP Assuming 85 % eff on Gear pump
Can I add the HPS and say that the over all HP needed by the pump it is 4.448 HP?
this is being driven by a pulley that it is also running another tandem pump 18GPM at 4350 PSI assuming 95 % eff (piston pump eff)
Main Piston Pump input HP = 53.7 HP
Can I say that my overall input HP required from the Gas Engine is 58.192 HP?
Thanks.
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