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Efficiency Calculation For A VFD Drive

08/17/2016 2:23 AM

Dear sir,

In our cement plant,We are having a RABH fan for which we connected a 730KW motor.The details of the motor are Make:Crompton Greaves Limited. KW:730. Volts:690V.Rotor Amps:0.Rotor Voltage:0. RPM:990. Amps:730A Efficiency:95.8%.Frame:BTPC500F .Year of Mfg.03/2009.

This motor is connected to a ABB VFD.ACS800-04-1060-7. 730KW.

The power is fed to VFD through a transformer.The details of the transformer are Make:PETE Transformers.KVA:1000.HV voltage:6600.LV1 voltage:690V.LV2 Voltage:690V.HV Amps:87.5A.LV1 Amps:418.4 Amps.LV2 Amps:418.4A, 3Phase,50Hz,Connection Symbol:DYN11d).Impedance:4.48We have measured KW at different points.KW at HT braker of Transformer:726.2 KW.KW at the input to VFD:695KW.KW at the output of the VFD:647.65KW.Motor RPM at that time=925.8RPM.We want to increase motor speed further ,at least to 960-970 RPM.But,we are not sure whether motor withstands or not.The power meter at the transformer incoming is showing 726.2 KW.Please help me as my production can be improved if we can run the motor at higher speeds. Thanks,NVRSrinivas

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#1

Re: Efficiency calculation for a vfd drive

08/17/2016 5:16 AM

Change (reduce) the fan pitch to get greater motor speed!

(To all the others, this answer relates to our long gone VERY serious discussion on bathtub breaking.)

I know that many of you will just ignore this request for assistance,while others will direct him to ask the manufacturer, while others will suggest alternate gearing and such.

Please give him all your BEST help!! He really needs it.

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#3
In reply to #1

Re: Efficiency calculation for a vfd drive

08/17/2016 7:18 AM

It might be easier to trim the fan diameter.

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#2

Re: Efficiency calculation for a vfd drive

08/17/2016 5:28 AM

Some of those numbers seem rather strange. For instance, on a 690 V motor, the amps would not likely equal the KW.

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#4

Re: Efficiency Calculation For A VFD Drive

08/17/2016 9:44 AM

Motor Rating:

730 kW, 690 V, 50 Hz, 730 A, 990 RPM

Running Load:

Power Going out of Transformer/ Reading MV panel : 726.2 kW

Power at Input of VFD: 695 kW

Power at Output of VFD / Inverter or Motor Terminals: 647 kW @ 926 RPM

What power it consumes at 970 RPM ?

Rated Torque of 730 kW motor: 7045.65 N.m

Torque delivered to Fan at 647 kW @ 926 RPM: 6, 676 N.m

When Speed increased from 926 RPM to 970 RPM, Torque also increases

so Torque at 970 RPM = ?

T970RPM = T926 RPM * ( N970 RPM /N926RPM )2

T970RPM = 6676 * ( 970 / 926 )2

T970RPM = 7325.41 N.m

Power970RPM = 743 kW

Since 7045.65 N.m is the rated torque of motor and required torque at 970 RPM is 7325.41 N.m. Motor could not meet torque requirement of the load.

Note: Above calculations are only valid if Torque is around 94.7 % at ACS 800 Panel at 647 kW and 926 RPM)

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#8
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Re: Efficiency Calculation For A VFD Drive

08/17/2016 1:41 PM

I liked your response, since you laid it all out there. I was mistaken with my rules of thumb estimate.

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#5

Re: Efficiency Calculation For A VFD Drive

08/17/2016 11:09 AM

Basic "Afinity law of speed" for a centrifugal (quadratic) machine states that the power required by the load from the motor changes at the cube (3rd power) of the speed change.

All other factors will remain relatively constant, only the speed changes so you are increasing the speed by 5%, your power will likely increase to being 1.053

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#6

Re: Efficiency Calculation For A VFD Drive

08/17/2016 1:08 PM

Hire an appropriate ''outside'' (specialist/consultant) to assume liability if their recommended ''fix'' doesn't fix it...

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#7

Re: Efficiency Calculation For A VFD Drive

08/17/2016 1:40 PM

The motor nameplate mentions 990 rpm, but something appears mistaken about amp draw, with a power of 730 kW, and 690 V service, I see no way to draw 730 A, but only slightly more than 610 A for three phase service. I have no idea if your VFD can be pushed higher, and apparently you may be asking more of the motor than it deliver without leaking smoke.

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#9

Re: Efficiency Calculation For A VFD Drive

08/18/2016 1:44 PM

Beyond Mr. Niazi's excellent response, if your air temperature changes with the increased air flow, you may end up with a different load.

In paper mills, we will at times push the equipment to the design limit, which is usually temperature rise of the motor stator, all other components suitably sized. If you run the fan at such a speed to hit your 730A motor nameplate current reading, amperes of the 3 phases balanced to design specs that Compton-Greaves can supply you, assuming that your stator cooling systems are not fouled and that your ambient temperature falls below the rated (maybe 40C), then you will hit your production limit, and allow for normal equipment design life.

Auxiliary cooling, or very low ambient temperature, can allow higher loads, which then shifts the stress away from the motor winding temperature, and on to mechanical components, bearings, couplings, etc.

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