What does this mean?

Hello Guest, If you have a energy meter at your school then find the energy consumed (kwh) for a day. Divide it by 24 and you will get the average kw load of your school. ( mid you this average and not peak, for peak load you have to install a powermeter at source of supply). Your average kw load for a year is 456 kw...( quite a load for a school). Good luck

It's enough to keep a 60 watt light bulb burning continuously for 7610 years!

4,000,000 kWh means a 1000kW load for 4000 hours a year, (20 hours a day x 200 days) This would imply a power station of up to 1500 KVA or even more output.

The fuel can be estimated if the type is known.

The exact use cannot be guessed accurately.

At 2000 learners and staff it would mean that each person consumes about 500 watt.

This may seem high but the irrigation of the sports fields and heating consumes quite a lot of energy.

The 4,000,000 kWh per year also means that if a 10% saving can be achieved 400,000 kWh worth of resources can be saved.

Hopefully the education at the institution warrants the use of resources and contribution to Global warming, pollution etc.

Person/device/equipment consumes Energy (units: Ws or kWh, joule, calories too!)

It means a rather hefty cost !

http://www.ukpower.co.uk/running-costs-elec.asp

Are there some admin staff who can be chucked in the boiler ?

That means above conferences.

And then:

Energy/month = 4000000/10(because 2 months holiday)= 400000 KWH/month

And if one class uses 100 FLC 40W bulbs.

Your class will able to be lighted continuously for approximately: 4000000/100/40/1000=1000000 H (1 million hours).

I think that, Energy consumption is one of lessons at high school ????

KW says about load. That is at what rate you are drawing electric energy. If you spend 1KW for one hour that meens that you have drwan one unit of power. In short it is written as KWH. Electricity supplier charge per units you have spend. Hope clear to you.

Joules are a measure of energy. Watts measure the rate of energy used. If you heat up one litre of water by one degree C you use about 4000 joules of energy. (So if you heat it through 100 degrees you use 4000j x 100 = 400,000 joules.)

One watt is the use of energy at the rate of one joule per second.

So (in a perfect experiment) if you were using a one watt element it would take about 4000 seconds to heat a litre of water one degree. A 100 watt element (using 100 joules per second) would take 40 seconds. A kilowatt element (using 1000 joules per second) would take 4 seconds. By the way, to get a sense of the energy involved, if you were generating the heat manually - eg turning a generator with an excercise bike - you could probably squeeze out 200 watts and heat a litre of water by one degree in 20 seconds.

So one kilowatt is a rate of energy use - 1000 joules per second - about what you and four very fit friends could produce every second if you were all at a sprint on your excercise bikes (although not for very long).

A kilowatt hour is the amount of energy used if you could keep this up for one hour - so 1000 joules per second multiplied by 3600 seconds. A kilowatt hour is not a rate of energy use, it is an amount of energy used - 3,600,000 joules.

So your school used 3,600,000 x 4,000,000 joules = 14,400,000,000,000 joules in 2006. That's 40,000,000,000 (forty thousand million) joules each day of the year. In water-heating terms, that would heat 100,000 litres from ice to boiling every day of the year (an olympic pool every three days).

Do you go to an extremely big school?

(and remember, that's your school's use at the socket - from coal to outlet there's a lot of inefficiency).

Hi Guest.

1kW = 1,000 Watts, so the rest is easy, it is just simple maths.

Spencer.

1KW=1000W

Hi Guest.

That is right, so what is your question?

Spencer.

4 mega watt in 2006 = 4,000,000 / 365 days a year / 24 hours per day = 456.6210 kilowatts per hour or enough power to run 300 toaster ovens all day long without stopping since most resistive 110v household appliances of that sort run at roughly 1500 watts per hour. But yyour school is probably consuming most of that energy in the form of light bulbs computers and water heaters. Also, operational hours limit times of use to 8 hours or one third of the entire 24 hour day so the average usage per hour per day is 3 times 456 kwh or abot 1350 kwh; for example, 10,000 100 watt light bulbs(10000 units * 100 watts * 8 hrs per day = an average of 1000 kilowats per hour per day),500 200 watt computers(500 units * 200 watts * 8 hrs per day = an average of about 100 kilowatts per hour per day), 10 5 kilowat water heaters (10 units * 5 kw * 8 hrs per day = an average of 50kwh per day) which leaves 200 kwh per day that is used by other high power tungsten outdoor stadium and / or indoor gym and auditorium lighting at 1 or more kwh per hour each light bulb and various other electronic office euipment including but not limited to phone pbx,copy machines and a/v euipment.

Does that illucidate the subject for you?

At a unit price of approx 15p/KwH, that School sure is racking up a bill. Something like £3000 for every day it's open (on the basis of 200 days/year). Where on Earth is it ? Alaska, Siberia ?

Your school must be energy thirsty so much that I can hardly believe it. That means they'd be using over 1MW energy a day.

I guess if you live in the US it is possible; which i why Mr Bush said at a (Kioto?) tereaty once that 'We cannot agree to something that goes aginst the interest of our National Economy'.

I do not know how big a school you go to but, this is a tromendous amount of power bill, even on a yearly basis.

By the way, what are their course fees? No hard feelings ehhh?

Hi Isti80.

Could you please write that again in English so that we can understand you?

Spencer.

I guess I was in a hurry to say something and therefore, my spelling error (tromendous) for tremendous and yeah -4,000,000.00KW/1000=4,000.00MW/365=10.9589MW a day

This is such an enormous power consumption that no Kioto treaty could handle, for long.

MeaXaeM you're right also in that if the school is open for even less than seven days a week then that makes things look even worse.

I bet they have included all the employees private electricity bills too.

Scapolie in case you've got stuck with me quoting Mr Bush - It is true that soon after he came to power, he attended a Kioto (not sure about the spelling) treaty where he refused to sign a commitment where the US would have further agreed to reduce their carbon emission. My words may not be exact but a few years later I saw his statement was repeated again on TV when he was ready to subdue.

Hi Isti80.

Yes, and he is going to repeat that again this week at the UN conference on climate change.

Kyoto is spelled thus.

Spencer.

Thanx for the spelling.

I suspect it is a lot more power than used in most schools in the US, unless the poster is speaking of a fairly large school (university) of multiple buildings and using the electricity for more than lighting, and lab equipment.

My bad. That's 4 gigawatt for 2006. 4,000,000,000 watts / 365 days / 24 hrs per day = 456,621 watts o 456.621 kilowatts per hour. So, multiply by a facor of 1ooo for that error and also by 1.4 because the school is only open 5 out of seven days so you have to adjust the figures by 5/7 which is 1.4 or 140% of what I said earlier. Of course, these aren't exact figures but rough estimates. Then again, look up those numbers again and see if they said 4million watts or kilowatts; it makes all the difference.

Max out.

Kilowatt hour is a unit of energy. Kilowatt is a unit of power. Imagine an automobile. The bigger the engine the more power the car has. The fuel it burns represents the energy consumed. A bigger engine will burn the fuel quicker, but a little engine can burn just as much if it runs longer.

To produce 4,000,000 kWh of electricity, the average coal burning plant will consume 1,590 tons (U.S.) of coal, release 4,650 tons of CO₂, release 25 tons of sulfur dioxide, release 10 tons of NOx and release almost a pound of mercury into the air. The energy consumed is about equal to what 750 cars consume in fuel in a year under normal use.

In the USA the average cost of electricity is about $.09 per kWh. 4,000,000 represents about $360,000 of electrical cost.

So when you leave a room, turn the lights off.