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volume of water

06/20/2009 10:51 AM

How do I calculate the volume of water in a 6" pipe?

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#1

Re: volume of water

06/20/2009 11:07 AM

3.14156 x Bore Radius x Bore Radius x Pipe Length.

ALL Units in inches.... answer in cubic inches.

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#5
In reply to #1

Re: volume of water

06/20/2009 2:40 PM

So it would be 6" pipe = 3"x3.14=9.72" x 50' ( 12x50)= 600"

9.72" x 600" = 5832 cu. in.

231 cu. in = 1 gallon

5832" divided by 231=25.2 gallon ?

Is this correct?

Thanks in advance

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#6
In reply to #5

Re: volume of water

06/20/2009 2:48 PM

Pi * radius2 * length

So I think you're off, I only saw one radius in there (I think)

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#7
In reply to #6

Re: volume of water

06/20/2009 3:04 PM

OK so if the problem is volume oh h2o in a 6" pipe that is 50 ' long it would be:

r= pi r2

3.14 x 3 x 3=19.26"

length = 50' x 12"= 600"

600 x 19.26=14,556 sq.in.

231 sq in= 1 gallon

so: 14,556 divided by 231=62.5 ?

Hope that's it??

Thanks

tony

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#8
In reply to #7

Re: volume of water

06/20/2009 3:36 PM

Part of the problem I think is you are getting kinda casual with terms, which leads to confusion.

Tried to make a pretty - but don't have drawing tools here. I'll be as clear as I can:

To figure the Volume of water in a cylinder we start with Area X Length - stop and visualize. Just like a box, area of one side times the length of the other side.

So to figure the area of the "floor" (because it is easy)

1. Figure the area of the pipe "end".

2. Multiply by the length of pipe.

Lets go back to the area of a circle:

OK so if the problem is volume oh h2o in a 6" pipe that is 50 ' long it would be:

r= pi r2

3.14(pi) x 3(r) x 3(r)=19.26"(area) GOOD!

length = 50' x 12"= 600" This is a bit of Length X Width = Area

But we HAVE area = 19.26" Now multiply area by length (also in inches so you don't bobble)

And pick it up from there

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#9
In reply to #8

Re: volume of water

06/20/2009 5:31 PM

Units units units

length = 50' x 12"= 600" This is a bit of Length X Width = Area

Should be

length = 50' x 12" / 1' = 600" the length in inchs , not a area

Dimensional analisys.

Any way a 6" inch asa pipe does not have 6" in internal diameter, schedule have to consider, see here.

http://www.josephoat.com/pdf/asapipeschedule.pdf

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#12
In reply to #9

Re: volume of water

06/20/2009 5:46 PM

Should be

length = 50' x 12" / 1' = 600" the length in inchs , not a area

Well, no - my point was he shouldn't have been calculating an area there - maybe I wasn't clear - hope he got it.

length = 50' x 12" / 1' = 600" should be area times length in same units here. No 12" at all as area was calculated back above when we did the bit with pi.

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#14
In reply to #9

Re: volume of water

06/20/2009 9:20 PM

In plumbing it is the i.d. of the pipe (6")so the diameter is 6". The o.d. is of no consequence. We have to find the amount of water the 6" diameter (i.d.) that is 50' long will contain in order to calculate the proper size container it will require,to be drained without spilling.

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#11
In reply to #7

Re: volume of water

06/20/2009 5:38 PM

Tony

Take more care reading the answer on the calc.

600 x 19.26=14,556 sq.in.

600 x 19.26=11,556 sq.in.

11,556 divided by 231 =

Regards Woody

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#13
In reply to #11

Re: volume of water

06/20/2009 6:06 PM

Thanks Woody I see where my longhand went from 11556 to 14556. Big difference, thanks again.

Tony

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#16
In reply to #11

Re: volume of water

06/22/2009 11:23 AM

Jeez ..What a lot of mistakes....I shouldn't really have to check these simple calcs....but should have noticed!

3.14 x 3 x 3=19.26"

3 x 3 x 3.1416 = 28.27 sq inches

50 x 12 = 600 inches long

600 x 28.27 = 16,962 cubic inches

16,962 divided by 231 = 73.4 gallons

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#2

Re: volume of water

06/20/2009 11:17 AM

Same as any other cylinder volume

∏ * R2 * length.

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#3

Re: volume of water

06/20/2009 11:50 AM

Hi all you, despite the formula

area= r2 * pi

Is the first formula we learn to use , I allways wonder where to find a measuring tool that can , by sure, give me the RADIOUS os a circle.

Not a tape , pencil and paper doing the division diameter by 2 , neither reading a digital caliper , and use a calculator.

I use , since a teacher taught me this one

area= D 2 * PI / 4 , and as PI / 4 = 0.785 , i use

area = D2 *0.785 , and as I live in a Metric country I relate this number to the Especific weigth of steel 7.85 Kg/dm3

Just a mnemonic formula.

Gabriel , from Argentina

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#4
In reply to #3

Re: volume of water

06/20/2009 12:20 PM

Well OK, I'll confess

I *remember pi*r2, but I then *modify* to suit my current needs since as you say, you can't always get a handy measurement.

(circumference² * height) / (4 * pi) is one of the most useful if you can't get the elbow off the damned pipe! i.e. cannot get to an end for diameter or radius.

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#10

Re: volume of water

06/20/2009 5:37 PM

Hi Tonycaudill

The 6" you are using may be nominal or your pipe may be oval or deformed.

It would therefore be better to calculate using measured values.

The volume would then be

Pi * major diam * minor diameter / 4 * length.

iF your deformation is not constant you may have to use some or other method like Simpson's rule to get the real value.

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#15

Re: volume of water

06/22/2009 8:26 AM

Well, 6in = <...tap, tap, tap...> 0.152m Ø.

The area of this assumed circular pipe = pi/4 multiplied by the diameter squared, which is <...tap, tap, tap...> 0.0182m2.

500' = 6000", divided by 39.37 inches per metre, which is <...tap, tap, tap...> 152.4m.

The volume of the pipe is its cross-sectional area multiplied by its length, which is 152.4m x 0.0182m2 which is <...tap, tap....> 2.8m3 or 2800 litres to 2 sig.fig.

One could use log tables or even a slide rule, though it won't make any difference.

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