Voltage Drop Calculation for Generator?

Which is it? Alternator, or generator? Not that it matters.

Oh, that's easy. It's in the protocols in British Standard 7671.

You may need to be clear about voltage drop vs. voltage droop, and the contexts for each.

check this please

Voltage drop calculation

That's voltage drop of a conductor, not of an alternator.

You may find what you are looking for HERE.

At first you have to state if your generator will be connected with a grid [network] or will be isolated [island]-the generator dedicate to a load.

If the generator is connected to Grid then the current supplied will pass through busbar or cable, a step-up transformer and may be a short

overhead line. Since the Grid voltage and frequency could be considered constant then the generator speed and voltage will be adapted automatically.

If the generator is connected directly to the load-could be a step-up transformer and a step-down transformer and cable supply and so on, between the Generator terminal and load terminal-then the voltage drop up to load terminal has to be checked. You need to know the current, the power factor and the impedance for each part of the supply circuit and you may calculate partial voltage drop and summarizing the total drop.

Alternator nevertheless it is same meaning with generator it is usually referred to battery charger-in a vehicle mainly.

Dear Rajnish5404,

For 3 phase Alternator it is TERMINAL VOLTAGE + IMPEDENCE VOLTAGE = INDUCED VOLTAGE. Here, the Impedence Voltage is the Voltage Drop.

The Impedence Voltage is the VECTORIAL SUM and NOT arithmathic addition, and can be calculated as follows.

Iz = I x R + I x (Xl-Xc) where Xl is voltage drop on account of Inductance and Xc is Voltage drop on account of Capacitance.

DHAYANANDHAN.S