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Join Date: Oct 2012
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Torque Required To Rotate Horizontal Shaft Mixer

10/31/2012 3:07 PM

hello im designing a horizontal shaft 1 cubic meter capacity concrete mixer. all of the research I've done to find the right way to calculate torque has resulted in many different answers and methods, none of which are consisent.

The shaft has a 3 paddles per set to turn the concrete and 8 sets ie 24 paddles. the length of the drum is 1.27m and the width is .8m.

density of wet concrete is 2400kg/m^3 so mass is also 2400kg

the shaft turns at a 20 rpm. The time to reach that acceleraton should only take 5 seconds. It is turned by a gearbox connected to an AC motor.

the size of eaach paddle is .114m wide by .370m in length

I've used a formula that says force on an immersed object travelling through a fluid.

force= coeff drag*density/2*vel^2*area

using integration i got a formula for torque required for each set of paddles to be

3/8*coeff drag*density*angular vel*paddle width*paddle length^4

taking drag coeff =1.05 for flat plate

i got a torque of 8.865 Nm which seems ridiculously low

i also added the inertia of the system

T (torque) = I (moment of inertia) * angular accel.

=0.7206Nm

i worked out with these values that id need a power of 150 watts which seems far from accurate

The biggest problem I'm having is finding the correct formula and units to use. If someone can get me started I can do the calculations. I may have questions as I go along. Thanks in advance for your help!

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#1

Re: Torque Required To Rotate Horizontal Shaft Mixer

10/31/2012 4:32 PM

Did you multiply by the number of submerged paddles?

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#2

Re: Torque Required To Rotate Horizontal Shaft Mixer

10/31/2012 4:58 PM

Why would you do it that way?????????????????

Do like everybody else in the world and use a rotating drum with the paddles attached to the inside of the drum.

You could do that with 5HP.

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#3

Re: Torque Required To Rotate Horizontal Shaft Mixer

10/31/2012 5:07 PM

Have you ever tried moving cement. I think you may have to reevaluate your process on how your going to mix.

you don't have what you need.

What you need in an understanding of Rheology, viscousity.

not as far as something moving through the cement, Your looking at a mixer.

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#4

Re: Torque Required To Rotate Horizontal Shaft Mixer

10/31/2012 5:15 PM

I see no accounting for the fact that the mixer will tend to lift the concrete in the direction of rotation, therefore it is trying to rotate the entire mass and this is resisted by friction against the body of the mixer. In other words, is your drag coefficient accurate?

For comparison I have a horizontal shaft paddle blender that is used for blending powders, about half the density. It's about 2m long by .8m, has 8 paddles mounted in a spiral configuration and turns at 24.5 rpm. It has a 25hp motor, and runs up to around 110% draw on a typical 1200-1400kg mix.

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#5

Re: Torque Required To Rotate Horizontal Shaft Mixer

11/01/2012 9:11 AM

I was once asked to calculate the horsepower required to deliver paving mix by use of an Archimedes screw. To make a long story short, I gave up calculating and built a dynamometer that read out actual horsepower. It was nice because you could see the effects of different viscosity, temperature, admix, etc. When just the correct size rock gets lodged in the screw, the torque requirement increases dramatically. The calculations will get you so far, then you need data.

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#6

Re: Torque Required To Rotate Horizontal Shaft Mixer

11/02/2012 4:41 AM

This is an ideal candidate for pilot-scale trials and then scale-up from them.

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#7

Re: Torque Required To Rotate Horizontal Shaft Mixer

11/03/2012 3:01 PM

I have some problem with your drum : how do you introduce 1m^3 in a drum with a voulme of only 0.638 m^3? Or may be I am wrong so please compute the drum volume with the values you give D0.8mx1.27m and give the right volume.

How are the paddles arranged ? Do you have also stationary paddles or all 8 rows turn?

Usually for such a mixer the drum volume should be about ≈2x the content.

Concrete is NOT a fluid it is a paste and the formula you use is not the right one. You should look in books about chemical machines where this mixing is a often used process.

The best would be to look at data from different manufacturers and make a correct reverse engineering effort and then estimate your peculiar power need.

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#8

Re: Torque Required To Rotate Horizontal Shaft Mixer

06/18/2018 7:40 AM

hi,

you must calculate for the 1500liter means 1.5 cubic meter capacity. Because after mixing 1.5 cm raw materials compacts up to 1 cm.

So calculate the torque required to rotate or move the 2400kg x1.5 = 3600kg

So required torque to move 3600kg @ 1m( depends on your arm length) = 36000Nm

So you will require 36000Nm capacity gearbox.

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