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Heat Exchanger Flow

12/28/2013 8:57 AM

I want to know the water flow capacity required for the heat exchanger where the Temp of hot water inlet is 52 deg , temp of hot water outlet is 47 deg and temp of cold water inlet is 28 deg and temp of cold water outlet is 32 deg . Heat exchanger used is plate type with counter flow ( no of plates is 50 plates with 3 mm thickness of each plate).

Pl suggest

Nithin

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#1

Re: Heat exchanger flow

12/28/2013 9:17 AM

Are you trying to heat the cold water, or cool the hot water?

I would be very helpful (dam near necessity) to know the surface area and liquid volume of each plate in order to arrive at any meaningful number.

So, you're on your own.

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#2

Re: Heat exchanger flow

12/28/2013 9:50 AM

Did you check the manufacturer?

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#3

Re: Heat exchanger flow

12/28/2013 10:33 AM

It depends on the heat flow. When you know that you can work it out easily. Cold water flow is 5/4 x hot water, due to difference in ΔT. But it doesn't necessarily mean it will do the duty. It's down to the heat exchanger designer to get that right.

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#4

Re: Heat exchanger flow

12/28/2013 10:38 AM

Why pump water at all? From the sparse information you provided you could just pour 52° C water into a bucket made of 50 3mm thick diamond plates that has a thermometer immersed in the water. The plates are not diamond plate steel. They're diamond with a thermal conductivity of 22W/[cm*K]. When the water cools to 47° C from evaporation and heating the air, pour your cooled water out. I know that this is not what you wish to do but it does meet your criteria.

To make this absurd answer I had to make several assumptions. I will not waste my time playing 20 questions finding out what is the real situation.

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#5

Re: Heat exchanger flow

12/28/2013 11:34 AM

36gpm......

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#6
In reply to #5

Re: Heat exchanger flow

12/28/2013 12:13 PM

Of course it could be different according to the actual design you are addressing....

http://www.ewp.rpi.edu/hartford/~ernesto/F2011/EP/MaterialsforStudents/Libardi/Shah2003-Ch9.PDF

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#7

Re: Heat Exchanger Flow

12/28/2013 12:26 PM

From your information I can only make an energy balance assuming that the heat exchager is completely insulated. The temp difference of hot water is 52-47= 5°K, cold water will gain according to your data 32-28=4 °K.

Since the cp value is for both flows the almost the same (water) I can ONLY say that the cold flow will be 5/4 = 1.25x bigger than the hot flow. And NOTHING ELSE!

To have the flow magnitude one needs to know the AMOUNT of energy the heat exchager has to handle and this you do not give.

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#13
In reply to #7

Re: Heat Exchanger Flow

12/29/2013 6:32 AM

Yes, see #3

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#16
In reply to #13

Re: Heat Exchanger Flow

12/30/2013 4:04 AM

Sorry, but I wrote the answer as soon as I read the question without a look at all other comments. In fact I read the first and did not go further.

I give you a GA!

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#17
In reply to #16

Re: Heat Exchanger Flow

12/30/2013 12:35 PM

No problem but thanks anyway!

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#19
In reply to #17

Re: Heat Exchanger Flow

12/31/2013 6:04 AM

I have a principle: if you want to be respected you should give respect to the other!

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#8

Re: Heat Exchanger Flow

12/28/2013 2:47 PM

It depends on the size (especially surface area) of the heat exchanger.

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#9
In reply to #8

Re: Heat Exchanger Flow

12/28/2013 9:42 PM

Nope, it depends on joules in versus joules out and joules dumped. Since we know none of these i choose 42.

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#10
In reply to #9

Re: Heat Exchanger Flow

12/28/2013 9:54 PM

At least I didn't say only on the size. K too....

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#11

Re: Heat Exchanger Flow

12/29/2013 2:16 AM

Dear Mr.P.NithinKumar,

The Principle involved is HEAT LOST by THE HOT MEDIUM = HEAT GAINED BY THE COLD MEDIUM.

Important point in this principle - It involves HEAT TRANSFER Co.EFFICIENT, LOG MEAN TEMPERATURE, Quantity of Mass Flow, where the Equation will be

Q = U x A x Delta T = W ( Thot-Tcold) x Sp.Heat

Where Q = Total Heat involved for Transfer, U = OHTC, A = Heat Transfer Area and Delta = Log Mean Temp., W = cold water quantity to be circulated, Thot and T cold, is the Temp at out let and inlet. You have referred that the fluid is WATER in both cases, and hence Sp.Heat is 1.

But You have not mentioned the Quantity of Hot water at 52 Deg.C and unless it is known, the Total Quantity of Heat to Removed cannot be arrived and cold water Temp. Rise is only 4 Degree C

Hence your Equation will be

W hot x ( 52-47) = W cold x ( 32 x 28) where W is the quantity.

In the above Equation there are 2 unknowns and hence youhave to inform what is W hot since you want to know W cold.

I think you have understood.

DHAYANANDHAN.S

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#12
In reply to #11

Re: Heat Exchanger Flow

12/29/2013 3:41 AM

Your answer is correct.

However, as Good Name points out in his reply #7, your analysis can confirm that, while we DON'T know the HEAT FLOW, we DO know the ratio of the WATER FLOW rates:

W cold / W hot = ΔT hot / ΔT cold = ( 52 - 47 ) / ( 32 - 28 ) = 1.25

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#15
In reply to #12

Re: Heat Exchanger Flow

12/29/2013 9:32 AM

Dear Mr.Zvi,

The Original Post reads as "I want to know the water flow capacity required............"

THE CAPACITY REQUIRED (obviously cold water) is the NEED or to be Known, by the Original Poster. Based on that I have pointed out that I ave given details and concluded that 2 unknowns in an equation cannot be solved, which you also know.

As Mr. Code Master has suggested in his posting No.3, above, you have derived the Ratio, which in my opinion, WILL NOT SATISFY the Quiery by the Original Poster.

DHAYANANDHAN.S

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#14
In reply to #11

Re: Heat Exchanger Flow

12/29/2013 6:34 AM

Yes, see #3

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#18

Re: Heat Exchanger Flow

12/30/2013 8:58 PM

"water flow capacity" should be plural "capacities" and since you are dealing with rate of flow and volume for two separate system flows to achieve the temperature changes, you need a "Flowrater" on each water line. Then you know the rate of flow and the input temp and output temp for the warm water you will know the required capacity for that system. Then the same applies to the cold water system. Then you will be able to calculate and adjust for the variations in temperatures between the two systems to maintain the desired result. Get some Flowraters for a closed system or graduated barrels at the drains and a stopwatch.

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